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3 years ago

Triangle ABC is shown below with line DE passing through the center:

Mathematics

1 answer:

rusak2 [61]3 years ago

7 0

Answer:

D'E' be parallel to the original line

Step-by-step explanation:

Given

$\triangle ABC$

Line $DE$

$k = 3$ -- scale factor

Required

The relationship between $DE$ and $D'E'$

When $\triangle ABC$ is dilated by a scale factor of 3, $\triangle A'B'C'$ will be three times as big as $\triangle ABC$ .

Also:

Line $D'E'$ will be three times as long as $DE$

Since no further transformation is done on $\triangle ABC$ and line $DE$ , then $D'E'$ will be parallel to $DE$

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Help???????????!!!!!!!!!!!

Butoxors [25]

Salutations!

12 $\frac{2}{3}$

- 9 $\frac{3}{4}$

= $\frac{38}{3}$

Then,

- 9 $\frac{3}{4}$

- $\frac{39}{4}$

Next, our final answer:

= $\frac{35}{12}$

= 2 $\frac{11}{12}$

Our decimal would be 2.916667

Hopefully This Helps!!!

3 0

3 years ago

Stefan measured a weight of a package as 15.375 pounds. The actual weight of the package is 15.125 pounds.

Ainat [17]

15.375/15.125 x 100 =~98.4

The ~% is 98.4%
Error = ~2.6%

Part B

Be a near amount. Can be

5 0

3 years ago

Barry is trying to calculate the distance between point E(3, 1) and point F(4, 7). Which of the following expressions will he us

Alex777 [14]

Answer:

Option (1) is correct.

Barry uses the expression " square root of the quantity of 7 minus 1 all squared plus 4 minus 3 all squared " to find the distance between point E(3, 1) and point F(4, 7).

Step-by-step explanation:

Given : Barry is trying to calculate the distance between point E(3, 1) and point F(4, 7).

Distance between two points can be calculate using distance formula,

Distance formula states given two points P(a,b) and Q(c,d) the distance between P and Q can be calculated using the given expression ,

$D=\sqrt{(c-a)^2+(d-b)^2}$

Thus, distance between point E(3, 1) and point F(4, 7) can be calculate using above formula as ,

Here, a= 3 , b= 1 , c = 4 and d = 7

$D=\sqrt{(c-a)^2+(d-b)^2}$

Substitute above values, we get,

$D=\sqrt{(4-3)^2+(7-1)^2}$

$D=\sqrt{(1)^2+(6)^2}$

$D=\sqrt{37}$

Thus, Barry uses the expression " square root of the quantity of 7 minus 1 all squared plus 4 minus 3 all squared " to find the distance between point E(3, 1) and point F(4, 7).

Thus, Option (1) is correct.

6 0

3 years ago

Read 2 more answers

Write an equation of the circle with center (-7, 4) and radius 8.

Stels [109]

answer

(x+7)^2 + (y-4)^2 = 64

set up equation

the equation of a circle is (x - h)^2 + (y - k)^2 = r^2

where h is the center x coordinate and k is the center y coordinate

values

from the point (-7,4) we know that h = -7 and k = 4

since the radius is 8, r^2 = 8^2 = 64

plug in values

now that we have all the values, we plug them into (x - h)^2 + (y - k)^2 = r^2

(x - h)^2 + (y - k)^2 = r^2

(x - (-7))^2 + (y-4)^2 = 64

(x+7)^2 + (y-4)^2 = 64

7 0

3 years ago

A cheetah ran 300 feet in 2.92 secods. What was the cheetahs average speed in miles per hou? Show your work.

Tom [10]

Start by converting 300 feet to miles and 2.92 seconds to hours.

300 feet 1 mile
----------- x -------------- = ?
1 5280 feet

2.92 sec 1 hr
----------------- * ---------------- = ?
1 3600 sec

Reduce each of the above fractions. Then convert 300 feet
-------------- to the
2.92 sec

equivalent speed / rate in mph using the converstion factors you derived earlier.

6 0

4 years ago