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3 years ago

PLEASE HELP ASAP

Mathematics

1 answer:

Minchanka [31]3 years ago

4 0

Answer:

28495.5 ft

Step-by-step explanation:

V=(4 /3)π(r^2)

r=radius=diameter/2

165/2=82.5

(4/3)3.14(82.5^2)

(4/3) x3.14x6806.25=28495.5ft

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Which value is equivalent to 5x10^6

Art [367]

Answer:

5000000

Step-by-step explanation:

10^6 = 10 x 10 x 10 x 10 x 10 x 10

10^6 = 1000000

5 x 10^6

= 5 x 1000000

= 5000000

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2 years ago

Lucy needs to hire a host. Host A is offering his services for an initial $60 in addition to $13.25 per hour. Hostess B is offer

Oksanka [162]

Host A: 60+13.25h

Host B: 75+11.5h

60+13.25h =75+11.25h

subtract 11.25h from each side

60+2h = 75

subtract 60 from each side

2h = 15

divide by 2

h = 7.5

at 7.5 hours the two hosts will charge the same

4 0

3 years ago

Read 2 more answers

help 14 points the image 2 is the answer choices the answer answer choices for all the questions help plz

Sindrei [870]

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3 years ago

Use a 30degrees and -60degrees right triangle to find the exact value of the following trigonometric expression. Cot 30 degrees=

LuckyWell [14K]

The dirty little secret about trig is students mostly just need to understand the 45/45/90 right isosceles triangle and the 30/60/90 triangle, which is half an isosceles triangle.

I'm sure you have seen it many times already, so I'll remind you in the 30/60/90 right triangle the sides opposite those angles are respectively in the ratio $1: \sqrt{3}:2$ . Remember the smallest side is always opposite the smallest angle, etc. These make a right triangle because

$1^2 + \sqrt{3}^2 = 2^2$

So in this hypotenuse 2 triangle, the length 1 side is opposite the 30 degree angle and the $\sqrt{3}$ side is adjacent to it.

We could jump right to the answer but let's enumerate all the trig functions. Really you should memorize the sine and cosine so you can get these quickly.

$\cos 30^\circ = \dfrac{ \textrm{adjacent} }{ \textrm{hypotenuse} } = \dfrac{\sqrt{3}}{2}$

$\sin 30^\circ = \dfrac{ \textrm{opposite} }{ \textrm{hypotenuse} } = \dfrac{1}{2}$

$\tan 30^\circ = \dfrac{ \textrm{opposite} }{ \textrm{adjacent} }= \dfrac{1}{\sqrt{3}} =\dfrac{\sqrt{3}}{3}$

$\cot 30^\circ = \dfrac{ \textrm{adjacent} }{ \textrm{opposite}} = \dfrac{\sqrt{3}}{1} =\sqrt{3}$

$\sec 30^\circ = \dfrac{ \textrm{hypotenuse} }{ \textrm{adjacent}}= \dfrac{2}{\sqrt{3}}$

$\csc 30^\circ = \dfrac{ \textrm{hypotenuse} }{ \textrm{opposite}}= \dfrac{2}{1} = 2$

We want the cotangent, another way to get it is

$\cot 30^\circ = \dfrac{\cos 30^\circ}{\sin 30^\circ} = \dfrac{\sqrt{3}/2}{1/2} = \sqrt{3}$

8 0

3 years ago

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A large study of German children of Caucasian descent found that 46% have brown hair and that 25% have freckles. Nonetheless, yo

STatiana [176]

Answer:

Having brown hair and having freckles are not necessarily independent events

Step-by-step explanation:

We are given the following information in the question:

Percentage of children having brown hairs = 46%

Percentage of people children having freckles = 25%

But it cannot be concluded that

German children of Caucasian descent are brown‑haired with freckles =

$0.46\times 0.25 = 0.115 = 11.5\%$

This is not always true because of the following reasons:

Brown hair and having freckles are not necessarily independent events.

We can not assume that event of a child having brown hair is independent of the event of child having freckles. The events could be dependent as well.

The above will only be true when event of a child having brown hair is independent of the event of child having freckles.

If the events are independent then,

$P(A \cap B) = P(A)\times P(B)$

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3 years ago