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spayn [35]
3 years ago
15

7. A city lot is twice as long as it is wide, If its perimeter is 480 units, what are the dimensions of the lot?

Mathematics
1 answer:
g100num [7]3 years ago
3 0

Answer:

Step-by-step explanation:

P = 480

P = 2 length + 2 width

but we also know that

2width = length

so plug that into the length

P = 2(2width) + 2 width

480 = 4 width + 2 width

480 = 6 width

80 = width

160= length

see?

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ASAP please!
Reil [10]

Answer:

D).

Step-by-step explanation:

ln (e · e^x) = x2 + 4x + 3

ln e^(x+1) = x^2 + 4x + 3

Taking all terms to the power e:

e^(x + 1 )=  e^ (x^2 + 4x + 3)

x + 1 =  x^2 + 4x + 3

x^2 + 3x + 2 = 0

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8 0
3 years ago
Mellie bought a 120$ fishing rod for 15% off. How much did she pay after a 7% tax was added to the rod?
Sever21 [200]

Answer:

The answer is 109.14

Step-by-step explanation:

You have to take away 15% from 120$ which gives you 102$. Then you add 7% and that gives you 109.14

8 0
3 years ago
What is the area of the triangle?<br><br> /_\<br><br> 18.in<br> 14.in
stepan [7]

Answer:

A=126

Base

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6 0
3 years ago
Read 2 more answers
The proportions of blood types O, A, B, and AB in the general population of a particular country are known to be in the ratio 49
Morgarella [4.7K]

Answer:

The proportions differ significantly from those in the general population.

Step-by-step explanation:

We state our null and alternative hypotheses as

H0: p1= 49/100, p2= 38/100, p3= 9/100 and p4= 4/100 for a multinomial distribution involving four categories and n= 170

against

Ha: pi≠ pi0 for at least one value of i= 1,2,3,4

The significance level is set at ∝= 0.05

The test statistic under H0 is

χ² = ∑ (Oi- ei)²/ei

which has approximate chi square distribution with 3d.f  (n-1)

Computations: Under H0 the expected frequencies are

np10= Blood type O = 170 * 49/100= 83.3

np20 = Blood type A = 170 * 38/100= 64.6

np30 = Blood type B = 170 * 20/100= 11.76

np40 = Blood type AB = 170 * 4/100= 2.35

The value of χ² is computed as follows

Cell       Observed         Estimated        (Oi-ei)            (Oi-ei)²   (Oi-ei)²/ei

             Frequency      Frequency  

               Oi                    ei

1             87                        83.3               3.7               13.69        0.157

2            59                      64.6              -5.6                 31.36       0.531

3             20                     34                  -14                   196           9.8

<u>4               4                      6.8                -2.8                  7.84         1.96       </u>

<u>∑             170                    188.7                                                  χ²= 12.43  </u>

<u />

The critical region is <u>χ</u>²≥ χ²(0.05,3) = 7.82 for alpha = 0.05 and

<u>χ</u>²≥ χ²(0.01,3) = 11.34  for alpha = 0.01

As the calculated value lies in the critical region for both value of alpha we reject our null hypothesis and accept our alternate hypothesis. The proportions differ significantly from those in the general population.

6 0
3 years ago
How do you factor by finding the common monomial factor?
klemol [59]

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6 0
3 years ago
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