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Taya2010 [7]
3 years ago
10

A spring with k = 33.5 N/m has a

Physics
1 answer:
netineya [11]3 years ago
6 0

Answer:

M.E = 0.241 Joules.

Explanation:

<u>Given the following data;</u>

Spring constant, k = 33.5 N/m

Extension, e = 0.12m

Mass = 1.20kg

To find the mechanical energy (M.E);

Mathematically, mechanical energy is given by this formula;

M.E = ½ke²

Where;

  • k is the constant of elasticity (spring constant).
  • e is the extension of the string.  

Substituting into the equation, we have;

M.E = ½*33.5*0.12²

M.E = ½*33.5*0.0144

M.E = 0.4824/2

M.E = 0.241 Joules.

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D. Select fresh, small flowers that will match the décor

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A long, nonconducting cylinder (radius = 6.0 mm) has a nonuniform volume charge density given by αr2, where α = 6.2 mC/m5 and r
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5 0
4 years ago
Is my answer correct or no?
irinina [24]
 No your answer is incorrect. Would you like the correct one?
8 0
4 years ago
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I need help in my physics class and show me how it’s done
Korolek [52]

If we have the angle and magnitude of a vector A we can find its Cartesian components using the following formula

A_x = |A|cos(\alpha)\\\\A_y = |A|sin(\alpha)

Where | A | is the magnitude of the vector and \alpha is the angle that it forms with the x axis in the opposite direction to the hands of the clock.

In this problem we know the value of Ax and Ay and we need the angle \alpha.

Vector A is in the 4th quadrant

So:

A_x = 6\\\\A_y = -6.5

So:

|A| = \sqrt{6^2 + (-6.5)^2}\\\\|A| = 8.846

So:

Ay = -6.5 = 8.846cos(\alpha)\\\\sin(\alpha) = \frac{-6.5}{8.846}\\\\sin(\alpha) = -0.7348\\\\\alpha = sin^{- 1}(- 0.7348)

\alpha = -47.28 ° +360° = 313 °

\alpha = 313 °

Option 4.

4 0
4 years ago
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