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lubasha [3.4K]
3 years ago
10

Help please Cu + S CuS

Chemistry
1 answer:
SCORPION-xisa [38]3 years ago
6 0

Answer:

Hi.. U should do like this

Cu + S - - - >Cu2S

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What do helium (He), neon (Ne), and argon (Ar) have in common?
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Answer:

The answer is: D

Explanation:

A. They have the same number of electron energy shells.  Is false, all the elements are in different periods so, they have different number of lectron energy shells.

B. They are all Halogens.  No, is wrong, halogens are F, Cl ,Br

C. They have the same number of electrons.  is wrong, if they had the same number of electrons they must be they same element and they aren't the same.

D. They are all Noble gases. Yes, it's true they are noble gases, they are the first group in the periodic table from the right.

6 0
3 years ago
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Chlorophenols impart unpleasant taste and odor to drinking water at concentrations as low as 5 mg/m3. They are formed when the c
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Answer:

See explaination

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Please kindly check attachment for the step by step solution of the given problem.

4 0
3 years ago
The best way seperate salt fron wateris with the use of
ExtremeBDS [4]

You can boil or evaporate the water and the salt will be left behind as a solid. If you want to collect the water, you can use distillation. This works because salt has a much higher boiling point than water. One way to separate salt and water at home is to boil the salt water in a pot with a lid. So, I would say maybe oil.

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2 years ago
If molecule dissociates in water what does it do
natita [175]
It either forms a base or an acid...I think that's the answer you're looking for
4 0
3 years ago
What is the maximum mass of P2I4 that can be prepared from 8.80g of P4O6 and 12.37g of iodine according to the reaction:
Dvinal [7]
The balanced chemical reaction would be as follows:

<span>5P4O6 +8I2 ---> 4P2I4 +3P4O10

We are given the amount of reactants used for the reaction. We first need to determine the limiting reactant from the given amounts. We do as follows:

8.80 g P4O6 (1 mol / </span><span>219.88 g) = 0.04 mol P4O6
12.37 g I2 ( 1 mol / </span><span>253.809 g ) = 0.05 mol I2

Therefore, the limiting reactant is iodine since less it is being consumed completely in the reaction. We calculate the amount of P2I4 prepared as follows:

0.05 mol I2 ( 4 mol P2I4 / 8 mol I2 ) (</span><span>569.57 g / 1 mol) = 14.24 g P2I4</span>
8 0
3 years ago
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