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Neporo4naja [7]
3 years ago
7

I need help. Is this right? ITS SO

Physics
1 answer:
marishachu [46]3 years ago
4 0

Answer:

Yes, that is correct.

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69.2 m with a velocity of 1.40* 10^2 km/h.

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How many atoms of oxygen in the chemical formula 2 Ca(CIO2)2?<br> O 2<br> O 4<br> O 6<br> O 8
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N4M.6 A board has one end wedged under a rock having a mass of 380 kg and is supported by another rock that touches the bottom s
Hitman42 [59]

Answer:

it is safe to stand at the end of the table

Explanation:

For this exercise we use the rotational equilibrium condition

         Στ = 0

         W x₁ - w x₂ - w_table x₃ = 0

         M x₁ - m x₂ - m_table x₃ = 0

where the mass of the large rock is M = 380 kg and its distance to the pivot point x₁ = 850 cm = 0.85m

the mass of the man is 62 kg and the distance

            x₂ = 4.5 - 0.85

            x₂ = 3.65 m

the mass of the table (m_table = 22 kg) is at its geometric center

            x_{cm} = L/2 = 2.25 m

            x₃ = 2.25 -0.85

            x₃ = 1.4 m

let's look for the maximum mass of man

            m_{maximum} = \frac{ M x_1 -m_{table} x_3}{ x_2}

let's calculate

             m_{maximum} = \frac{ 380 \ 0.85 - 22 \ 1.4}{3.65}(380 0.85 - 22 1.4) / 3.65

             m_{maximum} = 80 kg

we can see that the maximum mass that the board supports without turning is greater than the mass of man

             m_{maximum}> m

consequently it is safe to stand at the end of the table

5 0
3 years ago
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