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suter [353]
3 years ago
9

How would the force of a test charge change if the electric field is doubled?

Physics
2 answers:
Stolb23 [73]3 years ago
7 0
<span>The force would double.</span>
nignag [31]3 years ago
4 0

Answer:

The force would double.

Explanation:

The region around a charged particle in which another charged particle experiences a force of attraction or repulsion is called electric field.

The force experienced by per unit test charge when placed in an electric field is called the electric field strength.

Electric field strength = Force / test charge

Force = test charge x electric field strength

if the electric field is doubled, then force also be doubled.

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A rifle of mass M is initially at rest, but is free to recoil. It fires a bullet of mass m with a velocity +v relative to the gr
Natali5045456 [20]

Answer:

V=-\dfrac{mv}{M}

Explanation:

Given that

Mass of rifle = M

Initial velocity ,u= 0

Mass of bullet = m

velocity of bullet =  v

Lets take final speed of the rifle is V

There is no any external force ,that is why linear momentum of the system will be conserve.

Initial linear momentum = Final  linear momentum

 M x 0 + m x 0 = M x V + m v

0 =  M x V + m v

V=-\dfrac{mv}{M}

Negative sign indicates that ,the recoil velocity will be opposite to the direction of bullet velocity.

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3 years ago
Why is a concave mirror is used a reflector in a torch light?​
tatiyna

Answer:

diverging light rays of the bulb are collected by the reflector.

Explanation:

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3 years ago
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Two 110 kg bumper cars are moving toward each other in opposite directions. Car A is moving at 8 m/s and Car Z at –10 m/s when t
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From the law of conservation of momentum
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v2= 8 m/sec
8 0
3 years ago
A failure of the red-sensitive nerves in the eye to respond to light properly causes
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A circular loop with radius r is rotating with constant angular velocity ω in a uniform electric field with magnitude E. The axi
inn [45]

Answer:

\Phi_{E} = E\pi r^2 \omega t

Explanation:

The electric flux is defined as the multiple of electric field and the area that the electric field passes through, such that

\Phi_{E} = \vec{E}\vec{A}

When calculating the electric flux, the angle between the directions of electric field and the area becomes important, especially if the angle is changing with time.

The above formula can be rewritten as follows

\Phi_{E} = EA\cos(\theta)

where θ is the angle between the electric field and the area of the loop. Note that, the direction of the area of the loop is perpendicular to the plane of the loop.

If the loop is rotating with constant angular velocity ω, then the angle can be written as follows

\theta = \omega t

At t = 0, cos(0) = 1 and the electric flux through the loop is at its maximum value.

Therefore the electric flux can be written as a function of time

\Phi_{E} = E\pi r^2 \omega t

3 0
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