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amid [387]
3 years ago
7

A 4.0 kilogram train going right at 6.0 meters per second bumps into a toy wagon moving the same direction at 2.0 meters per sec

ond. The model train has a final speed of 4.8 meters per second, and the wagon has a final speed of 5.2 meters per second. WHAT IS THE MASS OF THE WAGON? round answer to two significant digits.

Physics
1 answer:
aliya0001 [1]3 years ago
5 0

Answer: 1.5kg

Explanation:

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A sound source of frequency f moves with constant velocity (less than the speed of sound) through a medium that is at rest. A st
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Answer:

The correct answer is d

Explanation:

In this exercise they ask us which statement is correct, for this we plan the solution of the problem, this is a Doppler effect problem, it is the frequency change due to the relative speed between the emitter and the receiver of sound.

The expression for the Doppler effect of a moving source is  

f ’= (v / (v- + v_s) f  

From this expression we see that if the speed the sound source is different from zero feels a change in the  frequency.

The correct answer is d

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What two things do you need to know to describe the velocity of an object?
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The distance it traveled and the time that it took to travel that distance
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A fission reaction is one in which the weaker electrostatic repulsion force wins out over the ___________ nuclear force and, as
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The strong nuclear force is responsible for holding nuclei together
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If the jumping frog can give itself the same initial speed, regardless its direction. how is the maximum vertical height related
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A projectile motion is characterized by a motion whose path is alike to that of an arc. It already has its derived equations. For the maximum height H and the maximum range R, the equations are:

H = v₀²sin²θ/2g       ;       R = v₀²sin(2θ)/g

As you can observe, they are almost alike. Since they both contain v₀²/g, let's isolate this term for both equations:

v₀²/g = 2H/sin²θ
v₀²/g = R/sin (2θ)

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2H/sin²θ = R/sin (2θ)
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4 0
4 years ago
A monatomic ideal gas initially fills a container of volume V = 0.25 m3 at an initial pressure of P = 250 kPa and temperature T
Murrr4er [49]

Answer:

number of moles = 27.34 moles

the temperature of gas after it undergoes the isobaric expansion = 605 K

Explanation:

Given that:

V = 0.25 m³

P = 250 kPa

T = 275 K

V₂ = 0.55 m³

P₂ = 760 kPa

a)

Using ideal gas equation ; PV = nRT

n = \frac{PV}{RT}\\\\n =  \frac{250*10^3*0.25}{8.314*275}\\\\n = \frac{62500}{2286.35}\\\\n = 27.34 \ moles

b) To calculate the temperature of gas after it undergoes the isobaric expansion; we have:

  1. \frac{V_1}{T_1}= \frac{V_2}{T_2}\\\\\frac{0.25}{275}= \frac{0.55}{T_2}\\\\T_2=\frac{0.55*275}{0.25}\\\\T_2 = 605 K

4 0
4 years ago
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