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amid [387]
3 years ago
7

A 4.0 kilogram train going right at 6.0 meters per second bumps into a toy wagon moving the same direction at 2.0 meters per sec

ond. The model train has a final speed of 4.8 meters per second, and the wagon has a final speed of 5.2 meters per second. WHAT IS THE MASS OF THE WAGON? round answer to two significant digits.

Physics
1 answer:
aliya0001 [1]3 years ago
5 0

Answer: 1.5kg

Explanation:

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Science questions!! Please help!!
kondor19780726 [428]

Answer:

1. b

2. c

3. b

4. a

5. a

6. c

7. c

8. d

7 0
3 years ago
During the last shot of the game, the basketball goes from rest to 15 m/s and reaches the backboard in 0.41 s. What was the acce
Anna [14]

Answer: a= 37m

Explanation: V= 15 m/s (Velocity) t= 0.41s (time) formula: a= v/t

15 m/s / 0.41 (15 divided by 0.41) = 36.583m

There are 2 significant digits, 36, you look at the third digit, either round up or down in this case up to 36. a= 37m

5 0
3 years ago
Which of the following is not a reason fluorescent lamps are advantageous over incandescent lamps?
Wewaii [24]
The correct option is A.
Fluorescent lamps have many advantages over incandescent lamps and the options given in B, C and D are part of these advantages. The option given in A is a disadvantage and not an advantage. This is because, as a result of operating at an higher temperature, it will gives out and radiate more heat. 
8 0
4 years ago
Aparticlewhosemassis2.0kgmovesinthexyplanewithaconstantspeedof3.0m/s along the direction r = i + j . What is its angular momentu
svetoff [14.1K]

Answer:

\vec{L}=-30\frac{kgm^2}{s}\hat{k}

Explanation:

In order to calculate the angular momentum of the particle you use the following formula:

\vec{L}=\vec{r}\ X\ \vec{p}       (1)

r is the position vector respect to the point (0 , 5.0), that is:

r = 0m i + 5.0m j    (2)

p is the linear momentum vector and it is given by:

\vec{p}=m\vec{v}=(2.0kg)(3.0m/s)(\hat{i+\hat{j}})=6\frac{kgm}{s}(\hat{i}+\hat{j})   (3)

the direction of p comes from the fat that the particle is moving along the i + j direction.

Then, you use the results of (2) and (3) in the equation (1) and solve for L:

\vec{L}=-30\frac{kgm^2}{s}\hat{k}

The angular momentum is -30 kgm^2/s ^k

8 0
3 years ago
Vibrations that move through the ground carrying the energy released during an earthquake are called
Alekssandra [29.7K]
Answer is Seismic Wave
4 0
3 years ago
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