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Kitty [74]
3 years ago
11

Your image appears 3.0 m from a plane mirror. How far IS YOUR IMAGE IN RELATION TO YOU?*

Physics
2 answers:
Vsevolod [243]3 years ago
8 0

Answer:

Being a plane mirror the Image is formed 3 metres beyond the mirror . So total distance is 3+3 = 6metres

SCORPION-xisa [38]3 years ago
3 0
I believe the answer is 3+3=6 m
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The British gold sovereign coin is an alloy of gold and copper having a total mass of 7.988 g, and is 22-karat gold 24 x (mass o
matrenka [14]

Answers:

(a) 0.0073kg

(b) Volume gold: 3.79(10)^{-7}m^{3}, Volume cupper: 7.6(10)^{-8}m^{3}

(c) 17633.554kg/m^{3}

Explanation:

<h2>(a) Mass of gold </h2><h2 />

We are told the total mass M of the coin, which is an alloy  of gold and copper is:

M=m_{gold}+m_{copper}=7.988g=0.007988kg   (1)

Where  m_{gold} is the mass of gold and m_{copper} is the mass of copper.

In addition we know it is a 22-karat gold and the relation between the number of karats K and mass is:

K=24\frac{m_{gold}}{M}   (2)

Finding {m_{gold}:

m_{gold}=\frac{22}{24}M   (3)

m_{gold}=\frac{22}{24}(0.007988kg)   (4)

m_{gold}=0.0073kg   (5)  This is the mass of gold in the coin

<h2>(b) Volume of gold and cupper</h2><h2 />

The density \rho of an object is given by:

\rho=\frac{mass}{volume}

If we want to find the volume, this expression changes to: volume=\frac{mass}{\rho}

For gold, its volume V_{gold} will be a relation between its mass m_{gold}  (found in (5)) and its density \rho_{gold}=19.30g/cm^{3}=19300kg/m^{3}:

V_{gold}=\frac{m_{gold}}{\rho_{gold}}   (6)

V_{gold}=\frac{0.0073kg}{19300kg/m^{3}}   (7)

V_{gold}=3.79(10)^{-7}m^{3}   (8)  Volume of gold in the coin

For copper, its volume V_{copper} will be a relation between its mass m_{copper}  and its density \rho_{copper}=8.96g/cm^{3}=8960kg/m^{3}:

V_{copper}=\frac{m_{copper}}{\rho_{copper}}   (9)

The mass of copper can be found by isolating m_{copper} from (1):

M=m_{gold}+m_{copper}  

m_{copper}=M-m_{gold}  (10)

Knowing the mass of gold found in (5):

m_{copper}=0.007988kg-0.0073kg=0.000688kg  (11)

Now we can find the volume of copper:

V_{copper}=\frac{0.000688kg}{8960kg/m^{3}}   (12)

V_{copper}=7.6(10)^{-8}m^{3}   (13)  Volume of copper in the coin

<h2>(c) Density of the sovereign coin</h2><h2 />

Remembering density is a relation between mass and volume, in the case of the coin the density \rho_{coin will be a relation between its total mass M and its total volume V:

\rho_{coin}=\frac{M}{V} (14)

Knowing the total volume of the coin is:

V=V_{gold}+V_{copper}=3.79(10)^{-7}m^{3}+7.6(10)^{-8}m^{3}=4.53(10)^{-7}m^{3} (15)

\rho_{coin}=\frac{0.007988kg}{4.53(10)^{-7}m^{3}} (16)

Finally:

\rho_{coin}=17633.554kg/m^{3}} (17)  This is the total density of the British sovereign coin

6 0
3 years ago
A light body and a heavy body have the
Elena-2011 [213]

Answer:

The heavy body

Explanation:

The heavy body because it's heavier and the heavier something is the more kinetic energy it has.

Pretty sure this is correct

Hope it helps

7 0
3 years ago
Read 2 more answers
If a car moves with a speed of 50 km / h and thirty minutes later it has a speed of 30 km / h, it indicates that the car is slow
il63 [147K]
The car has slowed down because of the deceleration or decelerating force acting on it. The decelerating force acting on it is generated by the application of brakes or the frictional force acting in the opposite direction of car's motion.
4 0
3 years ago
A comet orbits a star in a strongly elliptical orbit. The comet and star are far from other massive objects. As the comet travel
Kruka [31]

Answer:

the kinetic energy decreases and the potential energy Increases.

Explanation:

as the comet travels away from the star it gains an energy which it posses because of its position or state.once the comet moves away form the star the kinetic decreases until its lost all together to where the potential energy starts increasing.

3 0
3 years ago
Read 2 more answers
A 40.0-μFcapacitor is connected across a 60.0 Hz generator. An inductor is then connected in parallel with the capacitor. What i
amm1812

Answer:

The value of the inductance is 175.9 mH.

Explanation:

Given that,

Capacitor C= 40.0\ \muF

Frequency = 60.0 Hz

The inductor and capacitor is connected in parallel, the voltage across each of these elements is the same.

We have,

V_{L}=V_{C}

Using ohm's law

I_{rms}\times X_{L}=I_{rms}\times X_{C}

X_{L}=X_{C}

2\pi f L=\dfrac{1}{2\pi f C}

L=\dfrac{1}{4\pi^2\times f^2\times C}

Put the value into the formula

L=\dfrac{1}{4\times\pi^2\times60.0^2\times40\times10^{-6}}

L=0.1759\ H

L=175.9\times10^{-3}\ H

L=175.9\ mH

Hence, The value of the inductance is 175.9 mH.

5 0
4 years ago
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