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Crazy boy [7]
3 years ago
12

Cuales son los reactivos y los productos en una ecuacion quimica

Chemistry
1 answer:
sveta [45]3 years ago
7 0

Answer:

el reactivo es la entrada y el producto es la salida o el resultado

Explanation:

You might be interested in
Claude spends $315 to rent a car. The car he rents costs $45 per day. He has a coupon for 2 free days. Complete the equation bel
Julli [10]
$315 is your total cost of all
rent = 45 * numbers of days
d = numbers of days
45d
2 days free
45(d-2) = 315
Divide 45 to both sides
d-2 = 7
Add 2 to both sides
d = 9
So he rented for 9 days.
Hope this helps
5 0
3 years ago
Can someone help me?
Oduvanchick [21]

Answer:

<u>an element with a large number of valence electrons and a large atomic radius</u>

Explanation:

Electronegativity means a tedency when an atom attracts bonding electrons in a covalent bond situation.

» If an atom has many valency electrons [ <em>empty</em><em> </em><em>orbitals</em><em> </em><em>i</em><em>n</em><em> </em><em>o</em><em>u</em><em>t</em><em>e</em><em>r</em><em>m</em><em>o</em><em>s</em><em>t</em><em> </em><em>s</em><em>h</em><em>e</em><em>l</em><em>l</em><em> </em>], it has difficulty in attracting electrons hence electronegativity low.

» If an atom is large, its nuclear attraction force of incoming electrons is low hence low electronegativity.

.

7 0
3 years ago
17. The density of a population would influence which limiting factor?
riadik2000 [5.3K]

Answer:

The answer is growth rate

Explanation:

it will help you

7 0
3 years ago
"Carbonyl fluoride, COF2, is an important intermediate used in the production of fluorine-containing compounds. For instance, it
Alex17521 [72]

Answer:

\boxed{\text{0.50 mol/L}}

Explanation:

The balanced equation is

2COF₂ ⇌ CO₂+CF₄; Kc = 9.00

1. Set up an ICE table

\begin{array}{ccccc}\rm 2COF_{2} & \, \rightleftharpoons \, & \rm CO_{2} & +&\rm CF_{4}\\2.00& & 0& & 0\\-x& & +x & & +x\\2.00 - x& & x & &x \\\end{array}

2. Solve for x

K_{c} = \dfrac{[\rm CO][ \rm CF_{4}]}{[\rm COF_{2}]^{2}} = 9.00\\\\\begin{array}{rcl}\dfrac{x^{2}}{(2.00 - x)^{2}} & = & 9.00\\\dfrac{x}{2.00 - x} & = & 3.00\\x & = &3.00(2.00 - x)\\x & = & 6.00 - 3.00x\\4.00x & = & 6.00\\x & = & \mathbf{1.50}\\\end{array}

3. Calculate the equilibrium concentration of COF₂

c = (2.00 - x) mol·L⁻¹ = (2.00 - 1.50) mol·L⁻¹ = 0.50 mol

\text{The equilibrium concentration of COF$_{2}$ at equilibrium is $\boxed{\textbf{0.50 mol/L}}$}

Check:

\begin{array}{rcl}\dfrac{1.50^{2}}{0.50^{2}} & = & 9.00\\\\\dfrac{2.25}{0.25}& = & 9.00\\\\9.00 & = & 9.00\\\end{array}

OK.

5 0
4 years ago
A gas at constant volume has a pressure of 2. 80 atm at 400. K. What will be the pressure of the gas at 360. K? 2. 52 atm 2. 94
katovenus [111]

Answer:

2.52atm for sure

Explanation:

We know that:

P1= 2.80atm

T1= 400k

T2= 360k

And we want to find P2= ?

We have an equation: P1/T1 = P2/T2

Multiple both side by T2 to remove it

P2 = 2.52

6 0
3 years ago
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