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Len [333]
3 years ago
15

Ammonia , NH3, equation stocihiometric balance

Chemistry
1 answer:
8090 [49]3 years ago
5 0
<h2>2 moles of NH³ </h2>

<h2>MARK ME BRAINLIST</h2>
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A chemist must prepare 575.mL of 1.00M aqueous sodium carbonate Na2CO3 working solution. He'll do this by pouring out some 1.58M
igor_vitrenko [27]

Answer : The volume in mL of the sodium carbonate stock solution is 364 mL.

Explanation :

According to dilution law:

M_1V_1=M_2V_2

where,

M_1 = molarity of aqueous sodium carbonate

M_2 = molarity of aqueous sodium carbonate stock solution

V_1 = volume of aqueous sodium carbonate

V_2 = volume of aqueous sodium carbonate stock solution

Given:

M_1 = 1.00 M

M_2 = 1.58 M

V_1 = 575 mL

V_2 = ?

Now put all the given values in the above formula, we get:

1.00M\times 575mL=1.58M\times V_2

V_2=363.92mL\approx 364mL

Therefore, the volume in mL of the sodium carbonate stock solution is 364 mL.

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3 years ago
Which defines the average kinetic energy of a system's particles?
ch4aika [34]
<h2>Answer:Temperature</h2>

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T is the temperature.

For general gases,

f=3

For a given degrees of freedom,average kinetic energy is directly proportional to temperature.

So,the average kinetic energy depends on temperature.

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