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andrezito [222]
2 years ago
11

1 Volume of certain amount of a gas at 25°C and

Chemistry
1 answer:
dalvyx [7]2 years ago
6 0

Answer:

P₂ =  50 mmHg

Explanation:

Given data:

Initial volume of gas = 80 mL

Initial pressure of gas = 100 mmHg

Final volume = 160 mL

Final pressure = ?

Temperature = constant

Solution:

The given problem will be solved through the Boyle's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

100 mmHg × 80 mL = P₂ × 160 mL

P₂ = 8000 mmHg. mL/ 160 mL

P₂ =  50 mmHg

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Finding percent composition is fairly easy. You only need to divide the mass of an element by the total mass of the compound. We can do this one element at a time.

First, let's find the total mass by using the masses of the elements given on the periodic table.

7 x 12.011 (mass of Carbon) = 84.077

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3 x 14.007 (mass of Nitrogen) = 42.021

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Add all of those pieces together.

84.077 + 5.04 + 42.021 + 95.994 = 227.132 g/mol is your total. Since we also just found the mass of each individual element, the next step will be very easy.

Carbon: 84.077 / 227.132 = 0.37016 ≈ 37.01 %

Hydrogen: 5.04 / 227.132 = 0.022189 ≈ 2.22 %

Nitrogen: 42.021 / 227.132 = 0.185 ≈ 18.5 %

Oxygen: 95.994 / 227.132 = 0.42263 ≈ 42.26 %

You can check your work by making sure they add up to 100%. The ones I just found add up to 99.99, which is close enough. A small difference (no more than 0.03 in my experience) is just a matter of where you rounded your numbers.

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What is Oxidation state of sulphur in Na2S4O6?Help me..​
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Answer:

oxidation state of sulphur=x

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