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andrezito [222]
3 years ago
11

1 Volume of certain amount of a gas at 25°C and

Chemistry
1 answer:
dalvyx [7]3 years ago
6 0

Answer:

P₂ =  50 mmHg

Explanation:

Given data:

Initial volume of gas = 80 mL

Initial pressure of gas = 100 mmHg

Final volume = 160 mL

Final pressure = ?

Temperature = constant

Solution:

The given problem will be solved through the Boyle's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

100 mmHg × 80 mL = P₂ × 160 mL

P₂ = 8000 mmHg. mL/ 160 mL

P₂ =  50 mmHg

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Answer:

Above the Curie temperature, a magnet permanently loses all or some of its magnetism. External magnetic fields: Strong, opposing magnetic fields can cause the magnetic domains to lose their orientation and relax into a lower state of energy where they are not aligned.

Explanation:

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Iron fillings are added to water,and sink to the bottom. Is this a mixture or a solution ?
alexandr402 [8]
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3 years ago
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A balloon occupies 1.50 L with 0.205 mol of carbon dioxide. How many moles would be required to increase the size of the balloon
Gekata [30.6K]

Answer:

0.683 moles of the gas are required

Explanation:

Avogadro's law relates the moles of a gas with its volume. The volume of a gas is directely proportional to its moles when temperature and pressure of the gas remains constant. The law is:

V₁n₂ = V₂n₁

<em>Where V is volume and n are moles of 1, initial state and 2, final state of the gas.</em>

<em />

Computing the values of the problem:

1.50Ln₂ = 5L*0.205mol

n₂ = 0.683 moles of the gas are required

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8 0
3 years ago
A _____ change occurs when a substance changes phase.
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3 0
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A sample of CH4 is confined in a water manometer. The temperature of the system is 30.0 °C and the atmospheric pressure is 98.70
kakasveta [241]

Explanation:

The given data is as follows.

  P_{atm} = 98.70 kPa = 98700 Pa,  

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      height (h) = 30 mm = 0.03 m (as 1 m = 100 mm)

Density = 13.534 g/mL = 13.534 g/mL \times \frac{10^{6}cm^{3}}{1 m^{3}} \times \frac{1 kg}{1000 g}

                = 13534 kg/m^{3}

The relation between pressure and atmospheric pressure is as follows.

             P = P_{atm} + \rho gh

Putting the given values into the above formula as follows.

            P = P_{atm} + \rho gh

               = 98700 Pa + 13534 \times 9.81 \times 0.03 m

               = 102683.05 Pa

               = 102.68 kPa

thus, we can conclude that the pressure of the given methane gas is 102.68 kPa.

8 0
4 years ago
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