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andrezito [222]
3 years ago
11

1 Volume of certain amount of a gas at 25°C and

Chemistry
1 answer:
dalvyx [7]3 years ago
6 0

Answer:

P₂ =  50 mmHg

Explanation:

Given data:

Initial volume of gas = 80 mL

Initial pressure of gas = 100 mmHg

Final volume = 160 mL

Final pressure = ?

Temperature = constant

Solution:

The given problem will be solved through the Boyle's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

100 mmHg × 80 mL = P₂ × 160 mL

P₂ = 8000 mmHg. mL/ 160 mL

P₂ =  50 mmHg

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Answer:

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When n = 2, q = (1/2)² = 1/4, so the fraction removed from phase 1 is (1 - 1/4) = 3/4 or 75%.

When n = 3, q = (1/2)³ = 1/8, so the fraction removed from phase 1 is (1 - 1/8) = 7/8 or 87.5%.

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