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arlik [135]
2 years ago
10

2. How many moles are in 2.43 x 1024 particles of Carbon Monoxide (CO)?

Chemistry
1 answer:
stiv31 [10]2 years ago
6 0

Answer:

= 14.63 × 10^{45} particles.

Explanation:

According to Avogadro's priciple:

1 mole of any substance is 6.02 × 10^{23} particles

∴ 2.43 x 10^{24} moles × 6.02 × 10^{23}

<u>= 14.63 × </u>10^{45}<u> particles.</u>

I hope this was clear and easy to understand.

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Question 6
ss7ja [257]

Answer:

He is probably studying <u>Geomorphology. </u>

Explanation:

Geology is the science that studies the composition, structure, dynamics, and history of planet Earth, the processes by which it has evolved including everything that has to do with its natural resources and with this the processes that affect the surface, and therefore, the environment.

Geomorphology is a branch of geosciences, more specifically geography and geology. One of his most interesting models explains the ways in which the earth's surface is the result of a consistent dynamic balance.

3 0
3 years ago
If you dilute 250 mL of 6.4 M lithium acetate solution to a volume of 750 mL, what will the concentration of this solution be?
Tresset [83]
The answer would be 1006.4
3 0
3 years ago
1.State the relationship between the following properties:
Diano4ka-milaya [45]

Answer:

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7 0
3 years ago
What is the molarity of a solution in which 58g of nacl are dissolved in 1.0l of solution?
Marat540 [252]
Molarity is moles of solute per liter of solvent, so convert 58 g NaCl to moles, then divide by 1 liter to get your answer
7 0
3 years ago
The PH of a 0.1 M MCl (M is an unknown cation) was found to be 4.7. Write the net ionic equation for the hydrolysis of M and its
Serggg [28]

Answer:

6.25 X10^{-9} = Ka

Kb= \frac{10^{-14}}{6.25 X10^{-9}}= 1.6X10^{-6}

Explanation:

The ionic equation for the hydrolysis of the cation of the given salt will be:

M^{+} + H_{2}O ---> MOH + H^{+}

The expression for Ka will be:

Ka = \frac{[H^{+}][MOH]}{[M^{+}]}

As given that the concentration of the salt is 0.1 M and pH of solution = 4.7, we can determine the concentration of Hydrogen ions from the pH

pH = -log [H⁺]

[H⁺] = antilog(-pH) = antilog (-4.7) = 2 X 10⁻⁵ M = [MOH]

Let us calculate Ka from this,

Ka = {2.5X10^{-5}X2.5X10^{-5}}{0.1} = 6.25 X10^{-9}

The relation between Ka an Kb is

KaXKb =10⁻¹⁴

Kb= \frac{10^{-14}}{6.25 X10^{-9}}= 1.6X10^{-6}

6 0
3 years ago
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