Answer:
The correct answer is control group.
Explanation:
A group used in a study or in an experiment, which does not get treatment by the scientists and is used as a foundation to determine the functions of the other tested subjects is known as the control group. The control group is only found in an experimental investigation.
The group in an experiment, which gets the variable being examined is known as an experimental group. The comparison of an experimental group is done with a control group in order to find the answers in an experiment.
The answer for the following problem is explained below.
- <u><em>Therefore 16.5 × 10^-3 grams of carbon dioxide is produced from the complete combustion.</em></u>
Explanation:
Given:
mass of methane = 6.00 × 10^-3 grams
+ 
→ 
+ 
Firstly balance the following equation:
Before balancing the equation:
→ 
After balancing the equation:
→ 
where;
represents methane molecule
represents oxygen molecule
represents carbon dioxide molecule
represents water molecule
+2 → + 2
16 grams of methane → 44 grams of carbon dioxide
6 × 10^-3 grams of methane → ?
= 
= 16.5 × 10^-3 grams of carbon dioxide is produced from the complete combustion.
<u><em>Therefore 16.5 × 10^-3 grams of carbon dioxide is produced from the complete combustion.</em></u>
1.5 × 10^-6 i would think
Answer:
The answer is
<h2>[OH-] = 1.66 × 10^-14 M</h2>
Explanation:
To find the [OH-] we must first find the pH and the pOH of the solution
That's
pH + pOH = 14
pOH = 14 - pH
To find the pH we use the formula
pH = -log [H3O+]
From the question
[H3O+] = 0.6 M
pH = - log 0.6
pH = 0.22
pOH = 14 - 0.22
pOH = 13.78
We can now find the [OH -] in the solution using the formula
pOH = - log [OH-]
13.78 = - log [OH-]
Find the antilog of both sides
We have the final answer as
<h3>[OH-] = 1.66 × 10^-14 M</h3>
Hope this helps you
Answer:
Its Mineral Rock
Explanation:
I just did it on edg and got it right.
