1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lerok [7]
1 year ago
13

I REALLY NEED THE HELP

Chemistry
1 answer:
timama [110]1 year ago
7 0

Answer:4

Explanation:number 4 is the right answer :)

You might be interested in
PLEASE HELP!!!
Elena L [17]

Answer:

no it should not that place is historical and so they should make where u can visit but protect it as a historical landmark

3 0
2 years ago
PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE H
vfiekz [6]

Answer:

AU9NJ-BLVHV-TCLJS-54YTB

6 0
2 years ago
Please help me I have not gone over this in like 8 months and can not remember how to do it
Leona [35]

Answer:

91%

Explanation:

Since you are just trying to find the yield, take the moles of the substance from the products and divide it by the mol value of the reactants. Multiply by 100 to find percentage

0.45 ÷ 0.41 = 0.91111...

91%

4 0
2 years ago
A 25.0 mL sample of an acetic acid solution is titrated with a 0.175 M NaOH solution. The equivalence point is reached when 26.6
joja [24]

<u>Answer:</u> The concentration of CH_3COOH comes out to be 0.16 M.

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is CH_3COOH

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=?M\\V_1=25mL\\n_2=1\\M_2=0.175M\\V_2=26.6mL

Putting values in above equation, we get:

1\times M_1\times 25=1\times 0.175\times 26.6\\\\M_1=0.1862M

Hence, the concentration of CH_3COOH comes out to be 0.1862 M.

4 0
2 years ago
The density of potassium, which has the BCC structure, is 0.855 g/cm3. The atomic weight of potassium is 39.09 g/mol. Calculate
Nimfa-mama [501]

Answer:

lattice parameter = 5.3355x10^-8 cm

atomic radius = 2.3103x10^-8 cm

Explanation:

known data:

p=0.855 g/cm^3

atomic mass = 39.09 g/mol

atoms/cell = 2 atoms

Avogadro number = 6.02x10^23 atom/mol

a) the lattice parameter:

Since potassium has a cubic structure, its volume is equal to:

v = [(atoms/cell)x(atomic mass)/(p)x(Avogadro number)]

substituting values:

v =[(2)x(39.09)/(0.855x6.02x10^23)]=1.5189x10^-22 cm^3

but as the cell volume is

a^3 =v

a=\sqrt[3]{v}=\sqrt[3]{1.5189x10^{-22} } = 5.3355x10^-8 cm

for a BCC structure, the atomic radius is equal to

r=\frac{ax\sqrt{3} }{4}=\frac{5.3355x10^{-8}x\sqrt{3}  }{4}=2.3103x10^{-8}cm

7 0
2 years ago
Other questions:
  • IF 500 mL of air contains 2.50x10^22 particles (atoms and molecules). how much particles do you inhale in one day if you breath
    11·1 answer
  • You can open a can of soda at room temperature and hear a hiss which of the following factors has change inside the container
    12·2 answers
  • Does brainy work with out Wi-Fi?​
    14·2 answers
  • What makes up the human body? (A)many different gases (B)carbon dioxide (D)many cells (C) minerals
    14·2 answers
  • Potassium sulfate and strontium acetate<br> Express your answer as a chemical equation
    5·1 answer
  • Write the chemichal formulae of the following compounds.1) Ammonium chloride2) calcium hydroxide​
    10·1 answer
  • A 1.00 L of a solution is prepared by dissolving 125.6 g of NaF in it. What would be the molarity of this solution?
    5·1 answer
  • If an element has 16 protons, 17 neutrons, and 16 electrons,what is the charge of the ion?
    7·1 answer
  • I need to describe the organization of the periodic table
    7·1 answer
  • The picture below shows Enchanted Rock, a pink granite rock formation located in the Llano Uplift ecoregion. This land is most l
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!