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Nookie1986 [14]
3 years ago
8

The box-and-whisker plot summarizes student scores on a physical fitness test. Students receive an award for scores at or above

the upper quartile. What is the lowest score a student can get to receive an award?
Mathematics
1 answer:
Lena [83]3 years ago
4 0

Answer:

74

Step-by-step explanation:

To receive an award, student must obtain a score at or above the upper quartile, from.tye boxplot, the upper quartile is depicted by the endpoint of the box. Hence, the upper quartile of the distribution is 74. Hence only stude Ts who score 74 and above will receive an award Hence, the minimum score required is 74.

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Which of the following is not a way to represent the solution of the inequality 2(x + 1) greater than or equal to 20?
Goshia [24]

Answer:

option C

A number line with a closed circle on  9 and shading to the left

Step-by-step explanation:

we have

2(x+1)\geq 20

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2x+2-2\geq 20-2

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Listed below are speeds (mi/h) measured from southbound traffic on I-280 near Cupertino, California (based on data from SigAlert
adell [148]

Answer:

Option (B) is the correct answer to the following question.

Step-by-step explanation:

Step-1: We have to find the Mean of the series.

The series is Given in the question 62 61 61 57 61 54 59 58 59 69 60 67.

Mean(\overline{x})=\frac{62+61+61+57+61+54+59+58+59+69+60+67}{12} = 60.67

Step-2: We have to find the Standard Deviation.

Let Standard Deviation be x.

Formula of Standard Deviation is: s= \sqrt{\frac{\sum(x_{i}+\overline{x})}{n-1}}

Put value in formula of Standard Deviation,

s= \sqrt{\frac{(62+60.67)^{2}+(61+60.67)^{2}+(61+60.67)^{2}+(57+60.67)^{2}+....(67+60.67)^{2}}{n-1}} = 40.75

Step-3: Then, we have to find the critical value by chi-square.

X_{1-\alpha/2}^{2}=3.82

X_{1-\alpha/2}^{2}=21.92

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\sqrt{\frac{(n-1).s^2}{X_{\alpha/2}^{2}} } = \sqrt{\frac{12-1}{21.92}.(4.075)^2 }\approx2.8868 \\ i.e 2.9

\sqrt{\frac{(n-1).s^2}{X_{\alpha/2}^{2}} } = \sqrt{\frac{12-1}{3.816}.(4.075)^2 }\approx6.9188 \\ i.e 6.9

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