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bagirrra123 [75]
3 years ago
15

Start with 2. Add 6 to each term to get the following term. What is the 6th term of the sequence?

Mathematics
1 answer:
Vladimir [108]3 years ago
8 0

Answer:

32

Step-by-step explanation:

We can either add all the terms.

2+6=8

2,8

8+6=14

2,8,14

14+6=20

2,8,14,20

20+6=6

2,8,14,20,26

26+6=32

2,8,14,20,26,32

The Sixth term is 32

or We can multiply 6 times 5 (30) and add 2, which would give us 32.

The reasoning behind this is that we are adding six five times (so six times five) and we are also adding the first term (2).

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levacccp [35]

36

area of square = s²

given s = 6 , then

area = 6² = 36



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3 years ago
Asking for the equation
Novay_Z [31]

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x=-6

Step-by-step explanation:

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5) Which graph shows the solution of the system of inequalities 2x - y<-6 and y < 2x - 3?
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2 years ago
Write the equation of the line that passes through the points (-6,-1) and (-4,2). Put your answer in fully simplified point-slop
Archy [21]

(\stackrel{x_1}{-6}~,~\stackrel{y_1}{-1})\qquad (\stackrel{x_2}{-4}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{(-1)}}}{\underset{run} {\underset{x_2}{-4}-\underset{x_1}{(-6)}}} \implies \cfrac{2 +1}{-4 +6} \implies \cfrac{ 3 }{ 2 }

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-1)}=\stackrel{m}{\cfrac{3}{2}}(x-\stackrel{x_1}{(-6)}) \implies {\large \begin{array}{llll} y +1= \cfrac{3}{2} (x +6) \end{array}}

4 0
1 year ago
Is the point (1, -3) a solution to the system? Show all work
Studentka2010 [4]

Answer:

The point P(1,-3) is not a solution to the system.

Step-by-step explanation:

Given  \left \{ {{y-x+2}} \right.  

Let a point be P(1,-3)

Here x = 1 ; y = -3

Substituting the values of x,y in the function

\left \{ {{y-x+2}} \right.

For y<x-1

-3 < 1-1

-3<0 (True)

now for,

y>-x+2

-3 > -1 + 2

-3 > 1 (False)

Hence the point is not a solution to the system.

6 0
3 years ago
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