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strojnjashka [21]
3 years ago
14

How are ions different from atoms

Physics
1 answer:
notka56 [123]3 years ago
3 0
Atoms are always neutral it means, the number of Protons & electrons are equal in them whereas ions are charged, the number is different depends on the kind of charge

Hope this helps!
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Which would require the greater energy; slowing down of the orbital speed of the Earth so it crashes into the sun, or speeding u
tresset_1 [31]

Answer: Speeding up the orbital speed of earth so it escapes the sun require the greater energy.

Explanation: To find the answer, we need to know more about the Orbital and escape velocities.

<h3>What is Orbital and Escape velocity?</h3>
  • Orbital velocity can be defined as the minimum velocity required to put the satellite in its orbit around the earth.
  • The expression for orbital velocity near to the surface of earth will be,

                   V_o=\sqrt{gR}

  • Escape velocity can be defined as the minimum velocity with which a body must be projected from the surface of earth, so that it escapes from the gravitational field of earth.
  • The expression for orbital velocity will be,

                    V_e=\sqrt{2gR}

  • If we want to get into the sun, we want to slow down almost completely, so that your speed relative to the sun became almost zero.
  • We need about twice the raw speed to go to the sun than to leave the sun.

Thus, we can conclude that, the speeding up the orbital speed of earth so it escapes the sun require the greater energy.

Learn more about orbital and escape velocity here:

brainly.com/question/28045208

#SPJ4

3 0
2 years ago
The escape speed from an object is v2 = 2GM/R, where M is the mass of the object, R is the object's starting radius, and G is th
Rom4ik [11]

Answer:

Approximate escape speed = 45.3 km/s

Explanation:

Escape speed

        v=\sqrt{\frac{2GM}{R}}

Here we have

   Gravitational constant = G = 6.67 × 10⁻¹¹ m³ kg⁻¹ s⁻²

   R = 1 AU = 1.496 × 10¹¹ m

   M = 2.3 × 10³⁰ kg

Substituting

    v=\sqrt{\frac{2\times 6.67\times 10^{-11}\times 2.3\times 10^{30}}{1.496\times 10^{11}}}=4.53\times 10^4m/s=45.3km/s

Approximate escape speed = 45.3 km/s

6 0
3 years ago
When the spring, with the attached 275.0 g mass, is displaced from its new equilibrium position, it undergoes SHM. Calculate the
topjm [15]

Answer:

The period of oscillation is 1.33 sec.

Explanation:

Given that,

Mass = 275.0 g

Suppose value of spring constant is 6.2 N/m.

We need to calculate the angular frequency

Using formula of angular frequency

\omega=\sqrt{\dfrac{k}{m}}

Where, m = mass

k = spring constant

Put the value into the formula

\omega=\sqrt{\dfrac{6.2}{275.0\times10^{-3}}}

\omega=4.74\ rad/s

We need to calculate the period of oscillation,

Using formula of time period

T=\dfrac{2\pi}{\omega}

Put the value into the formula

T=\dfrac{2\pi}{4.74}

T=1.33\ sec

Hence, The period of oscillation is 1.33 sec.

4 0
3 years ago
Two moles of an ideal monatomic gas are at a temperature of 345 K. Then, 2250 J of heat is added to the gas, and 870 J of work i
Lapatulllka [165]

Answer: The final temperature is 470K

Explanation: Using the relation;

Q= ΔU +W

Given, n = 2mol

Initial temperature T1= 345K

Heat =Q= 2250J

Workdone=W=-870J(work is done on gas)

T2 =Final temperature =?

ΔU =3/2nR(T2-T1)

ΔU=3/2 × 2 ×8.314 (T2 - 345)

ΔU=24.942(T2-345)

Therefore Q = 24.942(T2-345)+ (-870)

2250=24.942(T2-345)+ (-870)

125.09=(T2-345)

T2 =470K

Therfore the final temperature is 470K

5 0
3 years ago
What are the six different character traits scientists should have?
frozen [14]

careful observation, curiosity, logic, creativity, skepticism, and objectivity

3 0
3 years ago
Read 2 more answers
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