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brilliants [131]
3 years ago
14

Friction in machines is commonly reduced by using what?

Physics
1 answer:
Dominik [7]3 years ago
8 0
I am not sure if this is what your looking for but most machines use oil 
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Why does life hate me?
yKpoI14uk [10]

Answer:

felt that

Explanation:

6 0
3 years ago
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In certain ranges of a piano keyboard, more than one string is tuned to the same note to provide extra loudness. For example, th
Mama L [17]

Answer:

f = 5.65 Hz

Explanation:

The fundamental frequency of a string is given by following formula:

f = v/2L

where,

f = fundamental frequency

v = speed of wave = √(TL/m)

L = Length of String

m = Mass of String

T = Tension in String

Therefore,

f = √(TL/m)/2L

2f = √(T/Lm)

For initial condition:

T₁ = 600 N

f₁ = 110 Hz

2(110 Hz) = √(600 N/Lm)

√(600 N)/220 Hz =  √Lm

Lm = 0.01239 N/s²

Now, for changed tension:

2f₂ = √(540 N/0.01239 N/s²)

f₂ = 208.7 Hz/2

f₂ = 104.35 Hz

So, the beat frequency will be:

f = f₁ - f₂

f = 110 Hz - 104.35 Hz

<u>f = 5.65 Hz</u>

3 0
3 years ago
Which event may occur when ocean salinity increases?
Travka [436]

Answer:

sunlight in deeper location decreases

Explanation:

because the more salinity water has the harder it is to see and the harder it is for light to travel through the ocean

6 0
2 years ago
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If the forces on an object are not balanced than the object must be...
iVinArrow [24]

Explanation:

If the forces are not balanced on an object, the object experiences an overall net force. This will change the object's velocity.

6 0
3 years ago
(2) Put 5kg mass at left side (at 2m). This is fixed throughout the experiment! (3) Try to balance by putting 5kg mass at the ri
dmitriy555 [2]

We can conclude that as the mass on the right increases, the distance of the mass towards the right decreases. Also when the two masses balance, the net torque is zero.

<h3>What is torque</h3>

The torque experienced by an object a given position is the product of the applied force and the perpendicular distance of the object.

When 5 kg mass is at 2 m on the left, another 5 kg at 2 m on the right will balance it.

\tau _{net} = (2 \times 5 \times 9.8)  - (2 \times 5 \times 9.8)\\\\\tau _{net} = 0

<h3>Position of 10 kg mass on the right</h3>

Apply principle of moment

F_1r_1 = F_2r_2\\\\(m_1gr_1) = (m_2gr_2)\\\\r_2 = \frac{m_1gr_1}{m_2g} \\\\r_2 = \frac{m_1 r_1}{m_2} \\\\r _2 = \frac{5 \times 2}{10} \\\\r_2 = 1 \ m

<h3>Net torque</h3>

\tau_{et} = m_2gr_2 - m_1gr_1\\\\\tau_{et} = (10 \times 9.8 \times 1) - (5 \times 9.8 \times 2)\\\\\tau_{et} = 0

<h3>Position of the 20 kg mass</h3>

r_2 = \frac{5 \times 2}{20} \\\\r_2 = 0.5 \ m

<h3>Net torque</h3>

\tau_{et} = m_2gr_2 - m_1gr_1\\\\\tau_{et} = (20 \times 9.8 \times 0.5) - (5 \times 9.8 \times 2)\\\\\tau_{et} = 0

Thus, we can conclude that as the mass on the right increases, the distance of the mass towards the right decreases. Also when the two masses balance, the net torque is zero.

Learn more about principles of moment here: brainly.com/question/26117248

7 0
2 years ago
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