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lesya692 [45]
3 years ago
5

A gas at 200 K occupies a volume of 350 ml. What temperature is needed to increase the volume

Chemistry
1 answer:
Rudik [331]3 years ago
5 0

Answer: Temperature in constant pressure is 286 K

Explanation: If pressure remains constant, then V/T = constant.

V1 = 350 ml and T1 = 200 K and V2 = 500 ml.  V1/T1 = V2/T2

and T2 = T1· V2 / V1 = 200 K · 500 ml / 300 ml = 285,7 K

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Tems11 [23]

The cell membrane which is more fat permeable will be present at the end of the process.

Solvent extraction is a very important method if separating mixtures. The principle of solvent extraction is based on the idea of like dissolves like. A substance dissolves in the component of the system in which it is most soluble.

If a cell extract is dissolved in a nonpolar solvent, the cell membrane which is mostly permeable to nonpolar molecules will dissolve most in the solvent.

Learn more:brainly.com/question/14396802

6 0
2 years ago
Which of the following terms describes an accumulation of rocky, sandy, or clayey material deposited at the end of a glacier?
OLEGan [10]

Answer:

Option (D)

Explanation:

<u>Eskers are the long ridges that are comprised of rocks, sands and clay particles and are deposited towards the end of the glaciers</u>. These are fluvioglacial depositional features. These particles are exposed after the glaciers recede. These ridges are formed parallel to the earlier flow direction of ice. The size of eskers is generally smaller as it carries smaller particles such as rocks, sands, and gravels, in comparison to the different type of moraines. It is because the flow velocity decreases as the glaciers melt. So, these eskers are formed at the end of the glaciers.

Thus, the correct answer is option (D).

3 0
3 years ago
During science class, while studying mixtures, you mix together table salt and sand. Your teacher challenges you to separate the
olga2289 [7]
The property to be used is sieving. you get a bowl and a sieve when you pour the sand and salt,the salt being the small particle sieve to the bowl while the sand remain on the sieve as residue
7 0
3 years ago
An atom has a diameter of 2.50 Å and the nucleus of that atom has a diameter of 9.00×10−5 Å . Determine the fraction of the volu
chubhunter [2.5K]

Answer:

The fraction of the volume of the atom that is taken up by the nucleus is 4.6656\times 10^{-14}.

The density of a proton is 6.278\times 10^{14} g/cm^3.

Explanation:

Diameter of the atom ,d = 2.50 Å

Radius of the atom ,r = 0.5 d=0.5 × 2.50 Å = 1.25Å

Volume of the sphere= \frac{4}{3}\pi r^3

Volume of atom = V

V=\frac{4}{3}\pi r^3..[1]

Diameter of the nucleus ,d' = 9.00\times 10^{-5}\AA

Radius of the nucleus ,r' = 0.5 d'=0.5\times 9.00\times 10^{-5}\AA=4.5\times 10^{-5}\AA

Volume of nucleus = V'

V=\frac{4}{3}\pi r'^3..[2]

Dividing [2] by [1]

\frac{V'}{V}=\frac{\frac{4}{3}\pi r'^3}{\frac{4}{3}\pi r^3}

=\frac{r'^3}{r^3}=\frac{(4.5\times 10^{-5}\AA)^3}{(1.25 \AA)^3}

\frac{V'}{V}=4.6656\times 10^{-14}

The fraction of the volume of the atom that is taken up by the nucleus is 4.6656\times 10^{-14}.

Diameter of the proton ,d = 1.72\times 10^{-15} m = 1.72\times 10^{-13} cm

1 m = 100 cm

Radius of the proton,r = 0.5 d=0.5\times 1.72\times 10^{-13} cm=8.6\times 10^{-14} cm

Volume of the sphere= \frac{4}{3}\pi r^3

Volume of atom = V

V=\frac{4}{3}\times 3.14\times (8.6\times 10^{-14} cm)^3=2.664\times 10^{-39}cm^3

Mass of proton, m = 1.0073 amu = 1.0073\times 1.66054\times 10^{-24} g

1 amu = 1.66054\times 10^{-24} g

Density of the proton : d

d=\frac{m}{V}=\frac{1.0073\times 1.66054\times 10^{-24} g}{2.664\times 10^{-39}cm^3}=6.278\times 10^{14} g/cm^3

The density of a proton is 6.278\times 10^{14} g/cm^3.

5 0
3 years ago
A solid object has a mass of 1.62 lb and a volume of 190 mL.
Pachacha [2.7K]

The density of a solid object that has a mass of 1.62 lb and a volume of 190 mL is 3.87g/mL.

<h3>How to calculate density?</h3>

Density is the measure of the mass of matter contained by a unit volume. It can be calculated by dividing the mass of the substance by its volume.

According to this question, a solid object is said to have a mass of 1.62 lb and a volume of 190 mL.

1 pound = 453.592 grams

1.62 Ibs is equivalent to 734.82 grams

Density of the solid object = 734.82 grams ÷ 190 mL

Density = 3.87g/mL

Therefore, the density of a solid object that has a mass of 1.62 lb and a volume of 190 mL is 3.87g/mL.

Learn more density at: brainly.com/question/20337365

#SPJ1

8 0
1 year ago
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