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snow_lady [41]
2 years ago
5

Help! I am in a hurry! Will get brainliest if correct!

Chemistry
1 answer:
Citrus2011 [14]2 years ago
8 0
The answer is Chlorine
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If the half-life of hydrogen-3 is 11.8 years, after two half-lives the radioactivity of a sample will be reduced to one-half of
maw [93]

Answer:

False

Explanation:

Half life is the time period at which the concentration of the radioactive substance in decay reduced to half.

<u>Thus, if the hydrogen-3 has gone 2 half lives, it means that it has first reduced to its half and then again the half of what it was, i.e. 1/4</u>

Thus, after two successive half-lives, the concentration must be 1/4 of the initial concentration and hence, the statement is false.

4 0
3 years ago
Which of the following would increase the amount to dissolve a solid solute?
AVprozaik [17]

By stirring and increasing temperature, there is an increase in dissolving capacity of the solid solute.

<u>Explanation:</u>

If a solute is added to the solution, it doesn't get dissolve easily then we have to increase the temperature, which in turn increases the movement of the solvent (may be water) and the solute particles, thus increases the dissolving power of the solid solute. One more way is by constant stirring, that is by making more contact among the solvent as well as the solute particles there by increasing the solubility of solid solute.

5 0
3 years ago
A student combines 20.0 grams of hydrogen and 20.0 grams of oxygen in a reaction. According to the law of conservation of mass,
jekas [21]

Answer:

A)20.0grams

Explanation:

4 0
2 years ago
Read 2 more answers
Why do bicycles use gears
iren2701 [21]
It is for safety if you come to a sudden stop like newtons law say if an object is in motion it stays in motion until a force stops it if the bike suddenly stopped then you would fly off because you wold still be going. and the gear helps protect you. 
7 0
2 years ago
Calculate the mass of water produced when 42 g of propane, c3h8, is burned with 115 g of oxygen
gavmur [86]
The balanced combustion reaction of propane, C₃H₈, is

C₃H₈ + 5 O₂ → 3 CO₂ + 4 H₂O

Molar mass of propane: 44 g/mol
Moles of propane = 42 g * (1 mol/44g) = 0.9545 mol propane

Molar mass of oxygen: 32 g/mol
Moles of oxygen = 115 g * (1 mol/32 g) = 3.594 mol oxygen

Moles of oxygen needed to completely react propane:
0.9545 mol propane * (5 mol O₂/1 mol propane) = 4.7725 mol oxygen

Since the available oxygen is only 3.594 moles and propane needs 4.7725 moles, that means oxygen is our limiting reactant. We base the amount of water produced here.

Molar mass of water: 18 g/mol
Mass of water produced = 3.594 mol O₂ * (4 mol H₂O/5 mol O₂) * (18 g/mol)
Mass of water produced = 258.768 grams
6 0
3 years ago
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