Answer:
The answer to this question is given below in the explanation section. The correct answer is B.
Explanation:
The purpose behind to explore an integrated development environment is to learn more about the features of the environment.
So the correct answer is B.
For example, you can use visual studio to build asp.net application using c#, then you need to explore what features visual studio offering to you.
However, other options are incorrect. Because, you can learn more about syntax, error handling, and abstraction in the programming language, not in the IDE.
Answer
Directory Services
<u></u>
<u>Definition</u>
It is a type of software that is used to unify and customize the resources available at the network.
<u>Explanation</u>
This software is used to gather the information and addresses of all computers connected on the network.
It is a type of information store, where all the information related to resources (computer) and services of network has been stored. It also gives administrator rights to the single point to manage whole network resources.
This is the reason, Option "D" is the best choice for me as sole IT employ in a company. I will prefer directory services software to gather the information of all computers of organization and manage users in company.
Answer:
Not sure what language, but in python a super basic version would be:
val1 = 98
val2 = 87
val3 = 84
val4 = 100
val5 = 94
sum = val1 + val2 + val3 + val4 + val5
avg = sum / 5
print(avg)
Explanation:
Answer:
<em>C++.</em>
#include <iostream>
using namespace std;
////////////////////////////////////////////////////////////////
int main() {
int weekly_hours = 0;
int hourly_rate;
float gross_pay = 0;
cout<<"Enter weekly hours worked: ";
cin>>weekly_hours;
cout<<"Enter hourly rate: ";
cin>>hourly_rate;
cout<<endl;
////////////////////////////////////////////////
if (weekly_hours > 40) {
gross_pay = (weekly_hours*hourly_rate) + ((weekly_hours*hourly_rate)*0.5);
}
else
gross_pay = weekly_hours*hourly_rate;
cout<<"Weekly gross pay: $"<<gross_pay;
////////////////////////////////////////////////
return 0;
}