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galina1969 [7]
3 years ago
5

What is the probability that a random sample of 12 second grade students from the city in a mean reading rate of more than 96 wo

rds per minute?
Mathematics
1 answer:
adelina 88 [10]3 years ago
4 0

Complete Question

The reading speed of second grade students in a large city is approximately normal, with a mean of 90 words per minute (wpm) and a standard deviation of 10 wpm.

What is the probability that a random sample of 12 second grade students from the city in a mean reading rate of more than 96 words per minute?

Answer:

P(\=x >96 )=0.01884

Step-by-step explanation:

From the question we are told that:

Sample size n=12

Sample mean \=x =90

Standard Deviation \sigma=10

Generally

\sigma_x=\frac{\sigma}{\sqrt{10}}

\sigma_x=\frac{10}{\sqrt{12}}

\sigma_x=2.887

Generally the equation for P(\=x >96 ) is mathematically given by

P(\=x >96 )=P(Z>\frac{\=x-\mu_x}{\sigma_x})

P(\=x >96 )=P*(Z>\frac{90-96}{2.887})

P(\=x >96 )=1-P(Z

P(\=x >96 )=1-0.98116

P(\=x >96 )=0.01884

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Answer:

\boxed{Side \ Length \ of \ hot \ tub = 4.8\ ft.}

Step-by-step explanation:

Scale Factor = 5

Also,

B'C' = 24 feet

Since both are squares so both have all sides equal.

Sqaure A'B'C'D' is dilated by a scale factor of 5

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4 0
4 years ago
Solve these systems of equations Using the elimination method.
grandymaker [24]
A. 3x + y = 13 → 15x + 5y = 65
    x -  5y = 15 →     x -  5y = 15
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                                      16     16
                                        x = 5
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                                     -5y = 10
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b.    6x - y = 14
      2x + y = 12
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              x = 3¹/₄
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6(3¹/₄) - y = 14
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 - 19¹/₂       - 19¹/₂
             -y = -5¹/₂
             -1      -1
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        (x, y) = (3¹/₄, 5¹/₂)

c. 3x -  4y = 22 → 15x - 20y = 110
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8 0
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Step-by-step explanation:


6 0
3 years ago
Find sec s if tan s = 3/4 and s is in quadrant I.
LUCKY_DIMON [66]

Answer:

4/3.

Step-by-step explanation:

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5 0
3 years ago
8
Alik [6]

Answer:

<em>123 pens in Box A</em>

Step-by-step explanation:

To solve this we will rewrite the word problem as an equation...

5x (A)

x (B)

When Teddy moves 82 pens from A to B, he is subtracting 82 pens from Box A and adding 82 pens to Box B...

5x - 82 (Change in Box A - subtraction)

x + 82 (Change in Box B - addition)

The problem now states that Box A and Box B are equal...

5x - 82 = x + 82

--- subtract x from both sides ---

4x - 82 = 82

--- add 82 to both sides ---

4x = 164

--- divide both sides by 4 ---

x = 41 pens

Now, we replace the x in the expression "5x - 82" with 41...

5(41) - 82 = 205 - 82

205 - 82 = 123

123 pens in Box A

Hope this Helps!

3 0
2 years ago
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