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3 years ago

Why handpicking is necessary after winnowing?please mark as brainliest

Chemistry

1 answer:

GarryVolchara [31]3 years ago

8 0

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A 100. mL volume of 0.800 M calcium chloride is mixed with 400. mL of water to make 500. mL of solution. What is the final molar

strojnjashka [21]

Answer:

0.99mol/L

Explanation:

Molarity ( M) = # of moles of solute / volume of solution (L)

Volume of Solution = 100 mL or 0.1 L

Molarity ( M) = # of moles of solute / volume of solution (L)

Molarity (M) = 0.099 mol / 0.1 L = 0.99mol/ L

3 0

4 years ago

Describe the function of the PNS and<br> the CNS.

Alenkinab [10]

Answer: PNS, CNS is

Periferal nervous system. Central nervous system.

Explanation:

7 0

3 years ago

Studio

coldgirl [10]

Answer:

0.895 g/mL

Explanation:

Step 1: Given data

Mass of liquid Z (m): 2.763 lb

Volume of liquid Z (V): 5.93 cups

Step 2: Convert "m" to grams

We will use the relationship 1 lb = 453.59 g.

$2.763 lb \times \frac{453.59 g}{1lb} = 1,253g$

Step 3: Convert "V" to milliliters

We will use the relationship 1 cup = 236.59 mL.

$5.93cup \times \frac{236.59mL}{1cup} = 1.40 \times 10^{3} mL$

Step 4: Calculate the density of the liquid Z

The density (ρ) of the liquid Z is equal to its mass divided by its volume.

$\rho = \frac{m}{V} = \frac{1,253g}{1.40 \times 10^{3}mL } = 0.895 g/mL$

4 0

3 years ago

A gas occupies a volume of 0.2l at 25 kpa. What volume will the gas occupy at 2.5kpa

EleoNora [17]

Boyle's Law: P₁V₁ = P₂V₂

So (25 kpa)(0.21) = (2.5 kpa) V₂

(25 kpa × 0.21)/ 2.5 kpa = 2.1

2.1 = V₂

8 0

4 years ago

1.65g of zinc is used to make 8g of zinc iodide. How much iodine is required for this reaction?

creativ13 [48]

Answer:

6.45 g of iodine, I₂

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

Zn + I₂ —> ZnI₂

Next, we shall determine the mass of Zn and I₂ that reacted from the balanced equation. This can be obtained as follow:

Molar mass of Zn = 65 g/mol

Mass of Zn from the balanced equation = 1 × 65 = 65 g

Molar mass of I₂ = 127 × 2 = 254 g/mol

Mass of I₂ from the balanced equation = 1 × 254 = 254 g

SUMMARY:

From the balanced equation above,

65 g of Zn reacted with 254g of I₂.

Finally, we shall determine the mass of f I₂ needed to react with 1.65 g of Zn. This can be obtained as follow:

From the balanced equation above,

65 g of Zn reacted with 254g of I₂.

Therefore, 1.65 g of Zn will react with = (1.65 × 254)/65 = 6.45 g of I₂.

Thus, 6.45 g of iodine, I₂ is needed for the reaction.

4 0

3 years ago

Why handpicking is necessary after winnowing?please mark as brainliest​

Why handpicking is necessary after winnowing?please mark as brainliest