Answer:
A. 20.866%
Explanation:
First, we calculate molar mass of Li3PO3
Molar mass of Li3PO3 = 6.9 (3) + 31 + 16(3)
= 20.7 + 31 + 48
= 99.7g/mol
To calculate the percent composition of Lithium, we say:
Mass of lithium in compound/mass of compound × 100
% composition = 20.7/99.7 × 100
= 0.208 × 100
= 20.8%.
Hey there!
Ninety nine percent of the atmosphere is composed of oxygen and nitrogen! The atmosphere is composed of 78% nitrogen and 21% oxygen!
Hope it helps :D
Answer:
0.488 mol
Explanation:
By the ideal gas law:
PV = nRT
Where P is the pressure, V is the volume, n is the number of moles, R is the gas constant (0.082 atm.L/mol.K), and T is the temperature in K. Thus, after the reaction:
P = 2.92 atm
V = 4.50 L
T = 55.2°C + 273 = 328.2 K
PV = nRT
n = PV/RT
n = (2.92*4.50)/(0.082*328.2)
n = 0.488 mol
