The alcohol concentration of the mixed solution is 20%
Simplification :
Based on the given condition, formulate :
35% ×0.40 + 0.6 ×10% ÷{ 0.4+0.6}
Calculate the product :
Calculate the sum or difference : 
Any fraction with denominator 1 is equal to numerator : 0.2
Multiply a number to both numerator, denominator : 0.2 ×
Calculate the product or quotient : 
A fraction with denominator equals to 100 to a percentage 20%.
How do you find the concentration of a mixed solution?
In general when your are mixing two different concentrations together first calculate number of moles for each solution (n=CV ,V-in liter) then add them together it will be total moles,then concentration of mixture will be = total moles / total volume(liter).
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Answer:
Lmol⁻¹s⁻¹
Explanation:
The rate law of the given reaction is:-
Rate=k[A][B]
Wherem, k is the rate constant.
Given that:-
Rate = 0.36 mol/Lsec = 0.36 M/sec
[A] = 3.0 M
[B] = 1.0 M
Thus,
Applying in the equation as:-
0.36 M/sec =k × 3.0 M× 1.0 M
k = 0.12 (Ms)⁻¹ = 0.12 Lmol⁻¹s⁻¹
<u>The units of k = Lmol⁻¹s⁻¹</u>
Force = mass * acceleration
= 14 * 2 = 28N
Work done (energy) = Force * distance
= 28 * 5 = 140J
Wheres the finished equation...
Answer:
52.206 kg
Explanation:
From the given information:
Mass of hexane C6H14 = 
= 7391.9 g
Mass of octane C8H18 = 
= 2682.7 g
Mass of decane C10H22 = 
= 9225.4 g
However, recall that:
number of moles of an atom = mass/molar mass
∴
For hexane, no of moles = 7391.9 g/86.18 g/mol
= 85.77 moles
For octane, no of moles = 2682.7 g/114.23 g/mol
= 23.49 moles
For decane, no of moles = 9225.4 g/142.29 g/mol
= 64.84 moles
Therefore:
number of moles of CO2 produced = (6 × 85.77)+(23.49)+(10×64.84) moles
= 1186.51 moles
Finally, the mass of CO2 produced is:
= 1186.51 mol × 44 g/mol
= 52206.44 g
= 52.206 kg