Answer:
electrolysis is the process by which electric current is passed through a substance to effect a chemical change
Salts get dissolved in water because it has partial positive and negative charges. So option (c) is correct.
<h3>Why does salt dissolves in water?</h3>
The water molecules pull the Na and Cl ions apart while breaking the ionic bond which held them together. After the salt ions are pulled apart, they get surrounded by water molecules. The salt dissolves to form a homogeneous solution.
- The slightly positive portion of sodium is attracted to the slightly negative portion of oxygen on the water molecule. At the same time, the slightly electronegative chlorine moieties of NaCl are attracted to the slightly electropositive hydrogen moieties of water.
- In either case, no true bond is formed, the stronger covalent bonds of water (also commonly held by hydrogen bonds between water molecules) win, NaCl gets pulled apart, resulting in dissociation of Na+ and Cl- ions with the Na+ and Cl- ions setting loosely in place between the intact H₂O molecules. NaCl is then dissolved.
Salts are ionic and are expected to dissolve in water because water itself is polar. Therefore, ionic salts are expected to dissolve in polar solvents.
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The enamel is the strongest substance in our bodies mainly inside your mouth.
Let's investigate the substances involved in the reaction first. The compound <span>CH3NH3+Cl- is a salt from the weak base CH3NH2 and the strong acid HCl. When this salt is hydrated with water, it will dissociate into CH3NH2Cl and H3O+:
CH3NH3+Cl- + H2O </span>⇒ CH3NH2Cl + H3O+
Nest, let's apply the ICE(Initial-Change-Equilibrium) table where x is denoted as the number of moles used up in the reaction:
CH3NH3+Cl- + H2O ⇒ CH3NH2Cl + H3O+
Initial 0.51 0 0
Change -x +x +x
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Equilibrium 0.51 - x x x
Then, let's find the equilibrium constant of the reaction. Since the reaction is hydrolysis we use KH, which is the ratio of Kw to Ka or Kb. Kw is the equilibrium constant for water hydrolysis which is equal to 1×10⁻¹⁴. Since the salt comes from the weak base, we use Kb. Since pKb = 3.44, then. 3.44 = -log(Kb). Thus, Kb = 3.6307×10⁻⁴
KH = Kw/Kb = (x)(x)/(0.51 - x)
1×10⁻¹⁴/ 3.6307×10⁻⁴ = x²/(0.51-x)
x = 3.748×10⁻⁶
Since x from the ICE table is equal to the equilibrium concentration of H+, we can find the pH of the aqueous solution:
pH = -log(H+) = -log(x)
pH = -log ( 3.748×10⁻⁶)
pH = 5.43
Answer:
2S +3O2 =2SO3
Explanation:
2 at the front of sulphur is to equalize the 2 put in SO3.
