<u>Answer:</u> The concentration of chloride ions in the solution is 1.056 mol/L
<u>Explanation:</u>
The chemical equation for the reaction of lead (II) nitrate and magnesium chloride follows:
All the chloride ions are getting converted to lead (II) chloride
To calculate the number of moles, we use the equation:
Given mass of lead (II) chloride = 7.35 g
Molar mass of lead (II) chloride = 278.1 g/mol
Putting values in above equation, we get:
1 mole of lead (II) chloride produces 1 mole of lead ions and 2 moles of chloride ions.
So, moles of chloride ions = (2 × 0.0264) = 0.0528 moles
To calculate the molarity of solution, we use the equation:
Moles of chloride ions = 0.0528 moles
Volume of solution = 50.0 mL
Putting values in above equation, we get:
Hence, the concentration of chloride ions in the solution is 1.056 mol/L