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noname [10]
3 years ago
11

Which of the following is true about hydropower? It changes the surrounding ecosystem. It does not produce greenhouse gases. It

produces harmful radiation. It burns fossil fuels.
Chemistry
1 answer:
Whitepunk [10]3 years ago
3 0

Answer:

A

Explanation:

One of the main complaints about hydropower is that it will change the ecosystem. You can read about the history of any dam and you will find that most of them have involved evacuation. That means that farmland was lost and replaced by a lake behind the dam. The energy comes from water cascading over the top of the dam to its bottom.

It does not produce radiation.

It does not burn fossil fuels. It's clean and does not pollute the air.

So there are no greenhouse gases involoved.

You might be interested in
a substance is analyzed to have a percent composition of 74.186% sodium and 25.814% fluorine. calculate the empirical formula
Novosadov [1.4K]

Answer:

Na₂₆F₁₁

Explanation:

We find the moles of the substance assuming 100 g of the substance is present. Why do we take 100 g? Because then the percent of sodium/fluorine, would be the g of sodium/fluorine respectively:

74.186 g Sodium | 1 mol Sodium/23 g              =>       3.2255 mol Na    

25.814 g Fluorine | 1 mol Fluorine/19 g             =>       1.3586 mol F

Divide each by smallest number of moles:

3.2255/1.3586 = 2.37

1.3586/1.3586 = 1

Multiply by common number to get a smallest whole number:

2.37*11 = 26,

1*11 = 11

The empirical formula is Na₂₆F₁₁

5 0
3 years ago
In an organic structure, you can classify each of the carbons as follows: Primary carbon (1o) = carbon bonded to just 1 other ca
Alla [95]

The question is incomplete, complete question is :

In an organic structure, you can classify each of the carbons as follows: Primary carbon (1°) = carbon bonded to just 1 other carbon group Secondary carbon (2°) = carbon bonded to 2 other carbon groups Tertiary carbon (3°) = carbon bonded to 3 other carbon groups Quaternary carbon (4°) = carbon bonded to 4 other carbon groups How many carbons of each classification are in the structure below? How many total carbons are in the structure? How many primary carbons are in the structure? How many secondary carbons are in the structure? How many tertiary carbons are in the structure? How many quaternary carbons are in the structure?

Structure is given in an image?

Answer:

There are 10 carbon atoms in the given structures out of which 6 are 1° , 1 is 2° , 2 are 3° and 1 is 4°.

Explanation:

Total numbers of carbon = 10

Number of primary carbons that is carbon joined to just single carbon atom = 6

Number of secondary carbons that is carbon joined to two carbon atoms = 1

Number of tertiary carbons that is carbon joined to three carbon atoms = 2

Number of quartenary carbons that is carbon joined to four carbon atoms = 1

So, there are 10 carbon atoms in the given structures out of which 6 are 1° , 1 is 2° , 2 are 3° and 1 is 4°.

3 0
3 years ago
Where is the color rock located?
ludmilkaskok [199]
Ans: The fluorescent-colored rock stacks rise from the desert floor more than 20 miles south of the Las Vegas Strip. Crafted from local limestone, the boulders were painted in fluorescent hues before being stacked. The towers are between 25 and 35 feet tall.
3 0
3 years ago
A gas with a volume of 2 L at 25°C is placed into a container that is 4 L. What is the new temperature of the gas?
zalisa [80]

Answer:

Convert 539 torr to atm.

2.) A gas takes up 25.2 liters at 25oC. At 25oC, the gas can also take up 12.2 liters at 1500 torr. What was the pressure, in atm, of the original sample?

3.) A gas takes up 14.8 liters of 24oC. What temperature in kelvin is required to obtain a volume of 25.0 liters at constant pressure?

4.) How many moles of chlorine gas are present at 25oC, 762 torr, with a volume of 14.2 L?

5.) If "Bor" (thats the name of a person) has a sample of gas that has a volume of 8.2 liter at 25oC and 2 atm, how much volume will it take up if you decrease pressure to 1.5 atms and icrease temperature to 100oC?

6.) 25 liters of gas A is pumped into a container at 25oC and 760 torr with 20 liters of gas B at 25oC and 700 torr. Calculate the total pressure when both gases are pumped into a tank with 10 liters at 25oC.

7.) Calculate the mole fraction of oxygen when 200 torr of air (760 torr total) is oxygen.

8.) KClO3 is decomposed by the following reaction:

2KClO3(s) ---> 2KCl(s) + 3O2(g)

The O2 produced was collected by the displacement of water at 22oC at a total pressure of 760 torr. The volume of gas collected was 1.20 liters, and the vapor pressure of water at 22oC is 21 torr. Calculate the partial pressure of O2 in the gas collected and the mass of KClO3 in the sample that was decomposed.  

9.) Calculate the root mean square velocity of hydrogen gas at 25oC.

10.) What is the ratio of effusion between fluorine and chlorine?

1.) Just set up a simple ratio.

539 torr * (1 atm/760 torr) = 0.709 atm

2.) Use this formula:

P1V1 = P2V2

460 atm  * 1.20 liters = 839 torr * V2

V2= 0.658 L

3.) You will use the ratio P1V1 = P2V2 in order to solve this equation.

P1V1 = P2V2

25.2 liters * P1 = 12.2 liters * (1500 torr / 760 torr)

Note that you have to convert the torr to atm. The problem asks for the final pressure in atms. You could of just solved the ratio without the conversion, and converted the answer later. Either way is acceptable.

25.2 liters * P1 = 24

P1 = 0.956 atm

4.) Use the formula:

V1/T1 = V2/T2

14.8 liters / 297 torr = 25.0 liters / x

14.8 x = 7425

x = 502 K

5.) PV = nRT (the ideal gas law! Note: you will see this a LOT in gases, so memorize it)

n = PV/RT

P = (762 torr/760 torr) = 1.00atm

n = (1.00 atm * 14.2 L) / (298oK * 0.08206)

n = 0.582 moles

6.) PV = nRT

n = PV/RT

= (2 atm * 8.2 L) / (0.08206 * 298oK) = 0.671 moles

Now, you must remember that you are taking this amount and changing it some more. So, you do this again, this time, solving for VOLUME. (No, the initial 8.2 doesn't count, because you are manipulating the environment)

PV = nRT

V = nRT/P

=(0.671 moles * 0.08206 * 373oK) / 1.5 atm = 13.76 liters

7.) You must solve this twice for both gas A and B, then combine the individual pressures to obtain the final pressure. Use the Ideal Gas Law.

ngas a = PV/RT = (1 atm * 25 liters) / (0.08206 * 298 K) = 1.02 moles

ngas b = PV/RT = (1 atm * 20 liters) / (0.08206 * 298) = 0.818 moles

You know how many moles you have. The second part of the problem calls for a manipulation of the environment, which means that you will be solving for PRESSURE.

Pgas a = nRT/V = (1.02 moles * 0.08206 * 298K / 10.0 liters) = 2.49 atm

Pgas b = nRT/V = (0.818 moles * 0.08206 * 298 K / 10.0 liters) = 2.00 atm

2.49 atm + 2.00 atm = 4.49 atm

8.) This is a simple mole fraction. You know that air has a total of 760 torr. Since we are given that O2 directly contributes 200 of that, we can set up this ratio:

O2 pressure/ total pressure = 200 torr / 760 torr = 0.263 = 26.3%

9.) Remember that:

Ptotal = PO2 + PH2O = PO2 + 21 torr = 760 torr

PO2 = 739 torr

PV = nRT or n=PV/RT

P = 739 torr/760 torr = 0.972 atm

n = (0.972 atm * 1.20 liters) / (0.08206 * 295 K) = 0.0482 moles O2

The final answer calls for mass of the KClO3, not the O2. So we must find the number of moles of KClO3.

0.0482 moles O2 * (2 mol KClO3/3 mol O2) = 0.0321 moles KClO3

0.0321 mol KClO3 * (122.6 g KClO3 / 1 mol KClO3) = 3.94 grams KClO3

10.) Remember that urms formula is:

So, using that, let's fill in our variables and constants. R, for this equation is 8.3145 J/K*mol and T = 298 K.  Calculating for M =

MH2 = 1 g/mol * 2 mol (since H2 is diatomic) * 1 kg/1000g = 0.002 kg

(3 * 8.3145 * 298/ 0.002) = 3716581.5 (you have to take the square root of this) -----> 1928 m/s

11.) Both fluorine and chlorine are diatomic. The equation relating effusion and diffusion is:

Taking this, you take the square root of 70.90 g (which is the weight of Cl2), and divide it by the square root of 37.996 g (which is the weight of F2). The answer is 1.366. This means that fluorine effuses 1.366 times as fast as chlorine, which makes sense because F2 is smaller.

Explanation:

3 0
3 years ago
Lesson Four: Significant Figures in Calculations
MArishka [77]

Answer:

a) significant figures   b) decimal places

Multiplying/dividing ex: 1.33 * 4.4932 = 5.98 because the first component only has three sig figs while the second has five.

Adding/subtracting ex: 12.13 + 53.5763 = 65.71 we ignore the whole numbers and focus only on the decimal places. The first component only has two while the second has four. Hope this helps!

5 0
2 years ago
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