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Ilya [14]
3 years ago
13

The product formation was decreased when a substance b was added to an enzyme reaction. more substrate being added did not incre

ase the amount of produce formed. based on this we assume that substance b could be
Chemistry
1 answer:
borishaifa [10]3 years ago
7 0
When the product formation is decreased if a substance B is added to an enzyme reaction and more substrate being added would not increase the amount of produce formed, then we assume that substance b could be a noncompetitive inhibitor. This type of inhibitor would be one that would bind to the enzyme with or without the presence of a substrate in different sites at the same time. It would change the conformation of the enzyme and also the active sites. As a result, the substrate would not be able to bind to the enzyme more effectively than the usual. The overall efficiency would decrease.
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Write balanced nuclear equations for the following:(a) β⁻ decay of silicon-32
S_A_V [24]

The balanced nuclear equations for the following:(a) β⁻ decay of silicon-32 is (27,14)Si -> (0,-1)beta + (27,15)P

<h3>What is balanced nuclear equation?</h3>

A nuclear reaction is generally expressed by a nuclear equation, which has the general form, where T is the target nucleus, B is the bombarding particle, R is the residual product nucleus, and E is the ejected particle, and Ai and Zi (where I = 1, 2, 3, 4) are the mass number and atomic number, respectively. Finding a well balanced equation is critical for understanding nuclear reactions. Balanced nuclear equations provide excellent information about the energy released in nuclear reactions. Balancing the nuclear equation requires equating the total atomic number as well as the total mass number before and after the reaction using the rules of atomic number and mass number conservation in a nuclear reaction.

To learn more about nuclear equations visit:

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7 0
1 year ago
A 3.452 g sample containing an unknown amount of a Ce(IV) salt is dissolved in 250.0-mL of 1 M H2SO4. A 25.00 mL aliquot is anal
SOVA2 [1]

Answer:

1,812 wt%

Explanation:

The reactions for this titration are:

2Ce⁴⁺ + 3I⁻ → 2Ce³⁺ + I₃⁻

I₃⁻ + 2S₂O₃⁻ → 3I⁻ + S₄O₆²⁻

The moles in the end point of S₂O₃⁻ are:

0,01302L×0,03428M Na₂S₂O₃ = 4,463x10⁻⁴ moles of S₂O₃⁻. As 2 moles of S₂O₃⁻ react with 1 mole of I₃⁻, the moles of I₃⁻ are:

4,463x10⁻⁴ moles of S₂O₃⁻×\frac{1molI_{3}^-}{2molS_{2}O_{3}^-} = 2,2315x10⁻⁴ moles of I₃⁻

As 2 moles of Ce⁴⁺ produce 1 mole of I₃⁻, the moles of Ce⁴⁺ are:

2,2315x10⁻⁴ moles of I₃⁻×\frac{2molCe^{4+}}{1molI_{3}^-} = 4,463x10⁻⁴ moles of Ce(IV). These moles are:

4,463x10⁻⁴ moles of Ce(IV)×\frac{140,116g}{1mol} = <em>0,0625 g of Ce(IV)</em>

As the sample has a 3,452g, the weight percent is:

0,0625g of Ce(IV) / 3,452g × 100 = <em>1,812 wt%</em>

I hope it helps!

5 0
3 years ago
Which of the following can explain the daily change in sea level observed along a coast?
salantis [7]
The answer for the question above is A. the gravitational pull of the moon on the water near the coast. The sun and and the moon are responsible for the rising and falling of the ocean tides. The gravitational pull of the moon and the sun makes the water in the oceans bulge, causing a continuous change between high and low tide. 
5 0
3 years ago
Which of the following is not an external force that acts on rocks in the rock cycle? A) wind B) pressure C) ice D) water
miss Akunina [59]
Wind isn’t an external force that acts in the rock cycle.
4 0
3 years ago
Read 2 more answers
An empty water bottle is full of air at 15°C and standard pressure. The volume of the bottle is 0. 500 liter. How many moles of
drek231 [11]

The moles of gas in the bottle has been 0.021 mol.

The ideal gas has been given as the gas where there has been negligible amount of interatomic collisions. The ideal gas equation has been given as:

PV=nRT

<h3>Computation for the moles of gas</h3>

The gi<em>ve</em>n gas has standard pressure, P=1\rm atm

The volume of the gas has been, V= 0. 500 \;\rm  L

The temperature of the gas has been, T=15^\circ \text C\\&#10;T=288\;\rm K

Substituting the values for the moles of gas, <em>n:</em>

<em />

<em />\rm 1\;\times\; 0. 500 =\textit n\;\times\;0.08214\;atm.L/mol.K\;\times\;288\;K\\\\&#10;\textit n=\dfrac{0. 500}{0.08214\;\times\;288} \;mol\\\\&#10;\textit n=0.021\;mol

The moles of gas in the bottle has been 0.021 mol.

Learn more about ideal gas, here:
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5 0
3 years ago
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