Question

point)A chemist has 4.43 g of lithium carbonate and must make a 0.0600 mol/L solution.What volume of solution can be made?a) 0.00197 Lb) 1.00 Lc) 250 mLd) 19.7 mL

Answer 1

Explanation:

A chemist has 4.43 g of lithium carbonate and must prepare a 0.0600 mol/L (or 0.0600 M) solution. We have to find the volume of solution that can be made.

The molarity of a solution is defined like:

molarity = moles of solute/volume of solution in L

We already know the concentration of the solution (it is 0.0600 mol/L) and the volume is our unknown.

volume of solution in L = ?

molarity = 0.0600 mol/L

We still have to convert the mass of lithium carbonate into moles. To do that we will use the molar mass of the compound.

lithium carbonate = Li₂CO₃

mass of Li₂CO₃ = 4.43 g

molar mass of Li₂CO₃ = 73.89 g/mol

moles of Li₂CO₃ = 4.43 g * 1 mol/(73.89 g)

moles of Li₂CO₃ = 0.0600 moles

Finally we can replace the values in the formula and solve it for the volume of solution.

molarity = moles of solute/volume of solution in L

volume of solution in L = moles of solute/molarity

volume of solution in L = 0.0600 mol/(0.0600 mol/L)

volume of solution in L = 1.00 L

Answer: b) 1.00 L