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anastassius [24]
3 years ago
12

What is the difference between an autosome and a sex chromosome

Chemistry
1 answer:
tatyana61 [14]3 years ago
8 0
. The members of theautosome pairs are truly homologous; that is, each member of a pair contains a full complement of the same gene.The sex chromosomes, on the other hand, do not constitute a homologous pair.
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Why does electronegativity increase as you move from left to right across
Katen [24]

Answer: increasing number of protons increases the positive charge of the nucleus.

Explanation: because as the electronegativity moves from left to right on the periodic table the protons do increase to make it into a positive charge.

7 0
3 years ago
As the volume of a gas at constant temperature did decreased,the pressure increases because
frosja888 [35]

Answer:

boyles law

Explanation:

volume is inversely proportional to pressure

7 0
3 years ago
Calculate the percentage difference in the fundamental vibrational wavenumbers of 23Na35Cl and 23Na37Cl on the assumption that t
stealth61 [152]

Answer:

1.089%

Explanation:

From;

ν =1/2πc(k/meff)^1/2

Where;

ν = wave number

meff = reduced mass or effective mass

k = force constant

c= speed of light

Let

ν =1/2πc (k/meff)^1/2  vibrational wave number for 23Na35 Cl

ν' =1/2πc(k'/m'eff)^1/2 vibrational wave number for 23Na37 Cl

The between the two is obtained from;

ν' - ν /ν  = (k'/m'eff)^1/2 - (k/meff)^1/2 / (k/meff)^1/2

Therefore;

ν' - ν /ν = [meff/m'eff]^1/2 - 1

Substituting values, we have;

ν' - ν /ν = [(22.9898 * 34.9688/22.9898 + 34.9688) * (22.9898 + 36.9651/22.9898 * 36.9651)]^1/2  -1

ν' - ν /ν = -0.01089

percentage difference in the fundamental vibrational wavenumbers of 23Na35Cl and 23Na37Cl;

ν' - ν /ν * 100

|(-0.01089)|  × 100 = 1.089%

4 0
3 years ago
Most of our DNA consists of regions that do not code for any proteins True or False
Lady bird [3.3K]
The Answer you are looking for is true
5 0
3 years ago
A particular voltaic cell operates with the reaction: Zn(s)+Cl2(g)--->Zn^2+(aq)+2Cl^-(aq) giving a cell potential of .853 V.
nadya68 [22]

Answer:

The amount of energy liberated will be 49.38 J.

Explanation:

The amount of energy liberated (gibbs free energy) can be calculated using the following equation:

ΔG° = -nFε

n: amount of moles of electrons transfered

F: Faraday's constant

ε: cell potential

20.0 g of Zn is equal to 0.30 mol.

Two electrons are transfered during the reaction.

Therefore, n = 2x0.30 ∴ n = 0.60

ΔG° = - 0.60 x 96.485 x 0.853

ΔG° = 49.38 J

3 0
4 years ago
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