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saveliy_v [14]
3 years ago
14

Which is one piece of information that "9” gives about an atom of fluorine?

Chemistry
2 answers:
Andru [333]3 years ago
5 0
9 is the atomic number
bonufazy [111]3 years ago
3 0

Answer:

The Atomic Number

Explanation:

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Nayla grew skin in a lab by adding cells to a synthetic material. The skin functioned normally for 12 days. Then Nayla separated
iris [78.8K]

Answer:B) The Skin and The Skin cells

Explanation:

Hope this helped

6 0
3 years ago
Find the volume of 3.011x1023 molecules of O2 at STP.
lord [1]

Answer:

6.022 x 1023 molecules = 1 Mole O2 = 22.4L

3.022 x 1023 molecules = 1/2 Mole O2 = 11.2L

The answer is 11.2 Litres

Explanation:

8 0
2 years ago
Convert 25 gram of carbon dioxide to mold
Rus_ich [418]

The atomic weight of carbon dioxide is about 12.011 + 15.999 + 15.999 = 44.009.

44.009 grams of CO2 = 1 mole of CO2             CO2 = Carbon dioxide

25 ÷ 44.009 ≈ 0.568

About 0.568 moles of CO2

7 0
4 years ago
Uranium is an element that is often used in nuclear power plants. Uranium atoms are very large, and the substance can be dangero
Allushta [10]

same number of protons and different number of neutrons are called isotopes

6 0
3 years ago
Calculate the energy for the transition of an electron from the n = 5 level to the n = 6 level of a hydrogen atom. E = Joules Is
kramer

Answer:

For an electron to move from a lower energy level to a higher energy , that electron needs to absorb energy sufficient enough to excite it to make the transition. Hence it is an absorption process. The required energy of transition  E = 2.665 x 10⁻²⁰J

Explanation:

Using the Rydberg's equation we can calculate the wavelength of the photon of energy transition as follows:

1/λ = R . (1/nf² - 1/ni²)

where

λ is the required wavelength of the photon needed to be absorbed to excite the electron to transit from level 5 to 6.  

(Note that for the electron to transit to from energy level 5 to 6, the photon would have to fall from level 6 to 5 in order to emit the required energy to excite the electron)

R is the Rydberg's constant 1.097 x 10⁷ m⁻¹

nf is the final level of the photon

ni is the initial level of the photon

1/λ = 1.097 x 10⁷ m⁻¹ (1/5² - 1/6²)

1/λ = 1.3407 x 10⁵ m⁻¹

λ = 7.458 x 10⁻⁶ m

This implies that that is the wavelength of the photon required to excite the electron to transit from energy level 5 to 6. Using the equation below, we can calculate the energy of transition as

E = h.c/λ

where

E is the required energy of transition

h is the Planck's constant (6.626 x 10⁻³⁴ Js)

c is the speed of light (3 x 10⁸ms⁻¹)

λ is the wavelength calculated above

E = 6.626 x 10⁻³⁴ Js  x  3 x 10⁸ms⁻¹/ 7.458 x 10⁻⁶ m

E = 2.665 x 10⁻²⁰J

3 0
3 years ago
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