Answer:
a) molarity of CCl3F = 1.12 × 10^-11 mol/dm³
Molarity of CCl2F2 = 2.20 × 10^-11 mol/dm³
B) molarity of CCL3F = 7.96 × 10 ^-13 mol/dm³
Molarity of CCl2F2 = 1.55 × 10^-12 mol/dm³
Explanation:
Using the ideal gas equation:
PV = nRT
Further explanations are found in the attachment below.
Answer:
Explanation:
When percentage composition is given, and asked for the empirical formula, it is simplest to assume 100 g of material. Thus,
Mass C = 40.92 g. Moles C = 40.92 g x 1 mole/12 g = 3.41 moles C
Mass H = 4.58 g. Moles H = 4.58 g x 1 mole/1.0 g = 4.58 moles H
Mass O = 54.50 g. Moles O = 54.50 g x 1 mole/16 g = 3.41 moles O
Now, we want to get the moles into whole numbers, so we begin by dividing all by the smallest, i.e. divide all values by 3.41.
Moles C = 3.41/3.41 = 1
Moles H = 4.58/3.41 = 1.34
Moles O = 3.41/3.41 = 1
Now, in order to get 1.34 to be a whole number we multiply it (and all others) by 3
Moles C = 1x3 = 3
Moles H = 1.34x3 = 4
Moles O = 1x3 = 3
Empirical Formula