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saveliy_v [14]
3 years ago
14

Which is one piece of information that "9” gives about an atom of fluorine?

Chemistry
2 answers:
Andru [333]3 years ago
5 0
9 is the atomic number
bonufazy [111]3 years ago
3 0

Answer:

The Atomic Number

Explanation:

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Which elements are necessary to accomplish work?
lawyer [7]

Answer:

D) force,cause, displacement

3 0
3 years ago
Read 2 more answers
Question 5
bagirrra123 [75]

Answer:

true

Explanation:

any object that is larger will take a longer time to do things, the same applies to heat levels. The lower the heat, the longer it takes, the higher the heat, the shorter it takes. So if an iceberg is large, it will need a higher heat, whereas an ice cube is really small and doesn't need that much heat to melt.

3 0
3 years ago
Prform the following operation and express the answer in scientific notation 6.0 x 10^3-2.310^3
Marrrta [24]

The value 6.0 x 10^3- 2.3 × 10^3 in scientific notation is 3.7 × 10^3.

<h3> What is scientific notation?</h3>

Scientific notation is a way to write very large or very small numbers so that they are easier to read and work with.

You express a number as the product of a number greater than or equal to 1 but less than 10 and an integral power of 10 .

<h3>Why it is used? </h3>

There are two reasons to use scientific notation.

  • The first is to reveal honest uncertainty in experimental measurements.
  • The second is to express very large or very small numbers so they are easier to read.

Given,

= 6.0 x 10^3- 2.3 × 10^3

= (6.0 - 2.3) × 10^3

= 3.7 × 10^3

Thus, we find that the value 6.0 x 10^3- 2.3 × 10^3 in scientific notation is 3.7 × 10^3.

learn more about scientific notation :

brainly.com/question/18073768

#SPJ1

3 0
2 years ago
A second-order reaction has a rate law: rate = k[a]2, where k = 0.150 m−1s−1. If the initial concentration of a is 0.250 m, what
Cerrena [4.2K]

Rate law for the given 2nd order reaction is:

Rate = k[a]2

Given data:

rate constant k = 0.150 m-1s-1

initial concentration, [a] = 0.250 M

reaction time, t = 5.00 min = 5.00 min * 60 s/s = 300 s

To determine:

Concentration at time t = 300 s i.e. [a]_{t}

Calculations:

The second order rate equation is:

1/[a]_{t} = kt +1/[a]

substituting for k,t and [a] we get:

1/[a]t = 0.150 M-1s-1 * 300 s + 1/[0.250]M

1/[a]t = 49 M-1

[a]t = 1/49 M-1 = 0.0204 M

Hence the concentration of 'a' after t = 5min is 0.020 M



7 0
3 years ago
If an ideal gas has a pressure of 5.49 atm, a temperature of 88.78 °c, and has a volume of 22.03 l, how many moles of gas are in
kirza4 [7]
N = (PV)/RT
(T = 88.78 + 273 = 361.78K)
(R = 22.4/273 = 0.082)
= (5.49 x 22.03)/(0.082 x 361.78) = ?
Put it into the calculator. It's hard to do that on a mobile phone.
7 0
3 years ago
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