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3 years ago

The common pathway for the oxidation of glucose and fatty acids is ________.

Chemistry

1 answer:

finlep [7]3 years ago

3 0

The citric acid cycle should be the answer.

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Wine goes bad soon after opening because the ethanol (CH3CH2OH) dissolved in it reacts with oxygen (O2) gas to form water and aq

andrezito [222]

The number of mole of oxygen needed is of 0.080 mole.

To solve this question, we'll begin by writing the balanced equation for the reaction. This is illustrated below:

From the balanced equation above,

2 moles of O₂ reacted to produce 2 moles of H₂O.

Finally, we shall determine the number of mole of O₂ needed to produce 0.080 mole of H₂O. This can be obtained as follow:

From the balanced equation above,

2 moles of O₂ reacted to produce 2 moles of H₂O.

Therefore,

0.080 mole of O₂ will also react to produce 0.080 mole of H₂O.

Thus, 0.080 mole of oxygen, O₂, is needed for the reaction.

Learn more: brainly.com/question/1563415

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3 years ago

Can you store cuso4 in an aluminum container? explain your reasoning

mash [69]

We can store the copper sulphate solution in alumiun container, if cover on alumiun is present.

<h3>Can you store cuso4 in an aluminum container?</h3>

Aluminium is more reactive than copper so the Aluminium will displace copper sulphate from its solution by reacting with it but if there is cover on the aluminium then the alumium can't react with copper.

So we can store the copper sulphate solution in alumiun container.

Learn more about container here: brainly.com/question/11459708

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2 years ago

What is the main cause of earthquakes?

Ahat [919]

Answer:

movement in tectonic plates. or volcanic eruptions.

Explanation:

5 0

3 years ago

Assume that the test tube shown started out having 10.00 g of mercury(II) oxide. After heating the test tube briefly, you find 1

anyanavicka [17]

This problem is providing information about the initial mass of mercury (II) oxide (10.00 g) which is able to produce liquid mercury (8.00 g) and gaseous oxygen and asks for the resulting mass of the latter, which turns out to be 0.65 g after doing the corresponding calculations.

Initially, it is given a mass of 10.00 g of the oxide and 1.35 g are left which means that the following mass is consumed:

$m_{HgO}^{consumed}=10.00g-1.35 g=8.65 g$

Now, since 8.00 grams of liquid mercury are collected, it is possible to calculate the grams of oxygen that were produced, by considering the law of conservation of mass, which states that the mass of the products equal that of the reactants as it is nor destroyed nor created. In such a way, the mass of oxygen turns out to be:

$m_{O_2}=8.65g-8.00g=0.65g$

Learn more:

3 0

2 years ago

If a cat goes meow what does that mean?

r-ruslan [8.4K]

Answer: HHHHHHHHHHHHHHHHHHHHHHAHAHHAHAHHAHHAHHAHHAHHAHAHAHHHAHAHAHHAHAHHA

DON"T KNOW?

Explanation:

6 0

3 years ago