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Marta_Voda [28]

3 years ago

10

The common pathway for the oxidation of glucose and fatty acids is ________.

1 answer:

finlep [7]3 years ago

3 0

The citric acid cycle should be the answer.

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Pls I need help give away 11 points

Maru [420]

Answer:

The charge is +2

Explanation:

Protons are positive, electrons are negative. 10-8=2.

+2 :)

7 0

3 years ago

Why is the "coming up" list on the dashboard useful?

kirill115 [55]

I'm teaching with Canvas. On my dashboard, under the Coming Up section, none of the assignments that are on the calendar (populated b/c they are "assignments") are displaying. The next one is due in 36 hours so I think it should display and it is listed on the calendar.

6 0

3 years ago

What is the new volume of a 61 L sample at STP that is moved to 183 K and 0.60 atm?

Volgvan

Answer: The new volume of a 61 L sample at STP that is moved to 183 K and 0.60 atm is 54.63 L.

Explanation:

Given: $V_{1}$ = 61 L, $T_{1}$ = 183 K, $P_{1}$ = 0.60 atm

At STP, the value of pressure is 1 atm and temperature is 273.15 K.

Now, formula used to calculate the new volume is as follows.

$\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}$

Substitute the values into above formula as follows.

$\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{0.60 atm \times 61 L}{183 K} = \frac{1 atm \times V_{2}}{273.15 K}\\V_{2} = 54.63 L$

Thus, we can conclude that the new volume of a 61 L sample at STP that is moved to 183 K and 0.60 atm is 54.63 L.

4 0

3 years ago

Why is excess magnesium oxide used in the formation of magnesium sulfate crystals?<br>

Tom [10]

I really don't know what the answer is

3 0

3 years ago

Read 2 more answers

1.00 L of gas at a standard temperature and pressure is compressed to 473mL. What is the new pressure of the gas?

Nadusha1986 [10]

Answer:

The pressure of the gas is 2.11 atm.

Explanation:

From the given,

$V_{1}=1.00\,L$

$P_{1}=1\,atm$

$P_{2}=?$

$V_{2}=473\,ml=0.473\,L$

$P_{1}V_{1}=P_{2}V_{2}$

$(1)(1)=(0.473)(P_{2})$

$P_{2}=\frac{(1)(1)}{0.473}=2.11$

Therefore, The pressure of the gas is 2.11 atm.

6 0

3 years ago