it's the first one. the one with ox in it
Answer:
Approximately .
Explanation:
The gallium here is likely to be produced from a solution using electrolysis. However, the problem did not provide a chemical equation for that process. How many electrons will it take to produce one mole of gallium?
Note the Roman Numeral "" next to . This numeral indicates that the oxidation state of the gallium in this solution is equal to . In other words, each gallium atom is three electrons short from being neutral. It would take three electrons to reduce one of these atoms to its neutral, metallic state in the form of .
As a result, it would take three moles of electrons to deposit one mole of gallium atoms from this gallium solution.
How many electrons are supplied? Start by finding the charge on all the electrons in the unit coulomb. Make sure all values are in their standard units.
.
.
Calculate the number of electrons in moles using the Faraday's constant. This constant gives the size of the charge (in coulombs) on each mole of electrons.
.
It takes three moles of electrons to deposit one mole of gallium atoms . As a result, of electrons would deposit of gallium atoms .
Answer:
The answer to your question is length is an extensive property
Explanation:
There are two physical properties: extensive and intensive properties.
An extensive property is a property that depends on the amount of matter.
An intensive property is a property that does not depend on the amount of matter.
Answer:
The correct answer is Mn
Explanation:
I hope you get the question right because I did!
Answer:
The rain drop of mass 0.050 g has 0.0028 moles of water.
Explanation:
We know that for each element or compound the molar mass of that compound is equal to 1 mole of that compound. So in the present case, the molar mass of water can be determined as sum of mass of two hydrogen atoms and one oxygen atom. Thus, the molar mass of water is found to be 18.01 g.
Since, 18.01 g of water = 1 mole of water
Then, 1 g of water = 1/18.01 mole of water.
But, here it is given that the raindrop contains 0.050 g of water, then
0.050 g of water = 0.050× moles = 0.0028 moles of water.
Thus, the rain drop of mass 0.050 g has 0.0028 moles of water.