9^18 just add the last number of each separate problem
30 bats, 3*10 for every block/intersection he passes, hope this is helpful!
To find our scale factor, let's determine the length of AB, and compare it to the length of A'B'.
The length of AB is the distance from (9,4) to (5,-4).
Let's apply the distance formula:
AB = √ ((9-5)² + (4+4)²)
AB = √ (4² + 8²)
AB = √(16 + 64)
AB = √ (80)
AB = 4 √5
The length of AB is 4 √5.
Now for A'B':
A'B' = √ ((6-5)² + (3+4)²)
A'B' = √( 1 + 49)
A'B' = √ 50
A'B' = 5 √2
To find our scale factor k:
A'B' = k AB
5 √2 = 4 √5 * k Divide both sides by 4√5
5 √2 / (4 √5) = k To simplify, multiply the left side by (√5 / √5)
(5 *√5 * √2) / (4 *5) = k the 5's in the numerator and denominator cancel
√5 * √2 / 4 = k
√10 / 4 = k
To confirm, make sure AB * k = A'B', using the values that we've calculated.
Answer:
0.0726 or 7.26%
Step-by-step explanation:
When choosing the first vial, there is a 16 in 58 chance that the vial does not have a hairline crack. When choosing the second vial, since on good vial was already picked, there is a 15 in 57 chance that the vial does not have a hairline crack. The probability that none of the 2 vials have hairline cracks is:

There is a 0.0726 or 7.26% chance that none of the 2 vials have a hairline crack.
Answer:
$30
Step-by-step explanation:
she makes $6 per hour
6x5=30