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3 years ago

If 28 grams of N reacts completely with 12 grams of H2, then how many

Chemistry

2 answers:

zhuklara [117]3 years ago

8 0

Answer:32 grams.

czts

Bogdan [553]3 years ago

5 0

Answer:

Mass of NH₃ produced = 34 g

Explanation:

Given data:

Mass of nitrogen = 28 g

Mass of Hydrogen = 12 g

Mass of NH₃ produced = ?

Solution:

Chemical equation:

N₂ + 3H₂ → 2NH₃

Moles of nitrogen:

Number of moles = mass/molar mass

Number of moles = 28 g/ 28 g/mol

Number of moles = 1 mol

Moles of hydrogen:

Number of moles = mass/molar mass

Number of moles = 12 g/ 2 g/mol

Number of moles = 6 mol

Now we will compare the moles of hydrogen and nitrogen with ammonia.

H₂ : NH₃

3 : 2

6 : 2/3×6 = 4 mol

N₂ : NH₃

1 : 2

Number of moles of ammonia produced by nitrogen are less thus it will act as limiting reactant.

Mass of ammonia produced:

Mass = number of moles × molar mass

Mass = 2 mol × 17 g/mol

Mass = 34 g

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<h2> $K_a$ = $\dfrac{[H^{+}] [A^{-}]}{[HA]}$ </h2>

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Here, $K_a$ is the dissociation constant of an acid.

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