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ad-work [718]
3 years ago
5

Water molecules contain what type of bonds

Chemistry
2 answers:
Semenov [28]3 years ago
8 0

Answer:

Hydrogen and oxygen bonds

Explanation:

suter [353]3 years ago
8 0
Water molecules have covalent bonds.
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10. If 3.5 kJ of energy are added to a 28.2 g sample of iron at 20°C, what
igor_vitrenko [27]

Answer:

569K

Explanation:

Q = 3.5kJ = 3500J

mass = 28.2g

∅1 = 20°C = 20 + 273 = 293K

∅2 = x

c = 0.449

Q = mc∆∅

3500 = 28.2×0.449×∆∅

3500 = 12.6618×∆∅

∆∅ = 3500/12.6618

∆∅ = 276.4220

∅2 - ∅1 = 276.4220

∅2 = 276.4220 + ∅1

∅2 = 276.4220 + 293

∅2 = 569.4220K

∅2 = 569K

3 0
2 years ago
A can was filled with crushed ice, sealed, and massed. The ice was melted by slowly warming the can and its contents. No water v
Lera25 [3.4K]

Answer:

A) The mass would be the same.

Explanation:

Since there is no loss of any particle to vapor during the phase change process from solid to liquid, the mass of the before and after the process will remain the same.

  • In this way, the law of conservation of mass is obeyed.
  • Mass is the amount of matter contained in a substance.
  • Since there is no room for escape or matter loss, the mass will remain the same.
8 0
3 years ago
Read 2 more answers
A solution of rubbing alcohol is 68.6 % (v/v) isopropanol in water. How many milliliters of isopropanol are in a 88.2 mL sample
KonstantinChe [14]


From the information given, the total volume of  rubbing alcohol is 88.2 ml

68.6 % of this volume is isopropanol. 

We will assume 88.2 ml represents 100% volume, so the volume of water will be 31.4 %

The volume of isopropanol is

68.6/100 x 88.2 → 0.686 × 88.2 = 60.505 ml

The volume of isopropanol is 60.5 ml.

Volume of water will be 88.20 - 60.5 = 27.7 ml

(27.7 / 88.2 × 100 = 31.4% )

Adding 60.5 ml of isopropanol to 27.7 ml of water to make up 88.2 ml will give 68.6 % v/v isopropanol to water  solution.



8 0
3 years ago
What is the electron configuration of bromine whose atomic number is 35
Vanyuwa [196]
1s22s22p63s23p64s23d104p5 is the answer
5 0
3 years ago
I am in desperate need of help will give 40 points to whoever helps me!!!!! I have a quiz tomorrow but I have no idea how to do
serious [3.7K]
All of the questions here are pertaining to the colligative properties of a solution and the preparation of solutions. Maybe, it would be best if you understand the equations to be used in order to answer these questions.<span>
Freezing point depression or Boiling point elevation:

</span><span>ΔT = -K (m) (i)

</span>ΔT is the change in the freezing point or the boiling point not the freezing point/boiling point. Therefore, it should be added to the original value of the property of the solvent. 
<span>
K is a constant called the molal freezing point depression constant and for the boiling point is the boiling point elevation constant. It is a property of the solvent. 
</span><span>
m is the concentration of the solute in the solvent in terms of molality or kg solute/kg solvent. 
</span><span>
i is the vant hoff factor which will represent the number of ions which the solute dissociates when in solution.</span>
5 0
3 years ago
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