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2 years ago

Which is a common unbalanced force acting on objects in motion?

Chemistry

2 answers:

stich3 [128]2 years ago

7 0

Answer:

hope it helps :)

Explanation:

Semmy [17]2 years ago

5 0

Answer:

a. friction

Explanation:

What is a common unbalanced force acting in motion? Common forces that are often unbalanced include the force of gravity and applied forces. When these forces are unbalanced, objects accelerate, change their position and find new configurations for which all forces are again balanced.

Friction is a kind of force.

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One isotope of a metallic element has the mass number 67 and 37 neutrons in the nucleus. The cation derived from the isotope has

Anuta_ua [19.1K]

No. Of protons = mass no. - no. Of neutrons
No. Of protons = 67 - 37
= 30
No. Of electrons = 28

Zinc will have 30 protons and 28 electrons. So, it will have +2 charge

Symbol - Zn^+2

6 0

3 years ago

Read 2 more answers

Which statement correctly describes the location and charge of the electrons in an atom?

maxonik [38]

Answer:

Explanation:

The electrons revolve around the nucleus and they contain negative charge

3 0

2 years ago

Using any data you can find in the ALEKS Data resource, calculate the equilibrium constant K at 30.0 °C for the following reacti

gayaneshka [121]

Answer : The value of $K$ for this reaction is, $2.6\times 10^{15}$

Explanation :

The given chemical reaction is:

$CH_3OH(g)+CO(g)\rightarrow HCH_3CO_2(g)$

Now we have to calculate value of $(\Delta G^o)$ .

$\Delta G^o=G_f_{product}-G_f_{reactant}$

$\Delta G^o=[n_{HCH_3CO_2(g)}\times \Delta G^0_{(HCH_3CO_2(g))}]-[n_{CH_3OH(g)}\times \Delta G^0_{(CH_3OH(g))}+n_{CO(g)}\times \Delta G^0_{(CO(g))}]$

where,

$\Delta G^o$ = Gibbs free energy of reaction = ?

n = number of moles

$\Delta G^0_{(HCH_3CO_2(g))}$ = -389.8 kJ/mol

$\Delta G^0_{(CH_3OH(g))}$ = -161.96 kJ/mol

$\Delta G^0_{(CO(g))}$ = -137.2 kJ/mol

Now put all the given values in this expression, we get:

$\Delta G^o=[1mole\times (-389.8kJ/mol)]-[1mole\times (-163.2kJ/mol)+1mole\times (-137.2kJ/mol)]$

$\Delta G^o=-89.4kJ/mol$

The relation between the equilibrium constant and standard Gibbs, free energy is:

$\Delta G^o=-RT\times \ln K$

where,

$\Delta G^o$ = standard Gibbs, free energy = -89.4 kJ/mol = -89400 J/mol

R = gas constant = 8.314 J/L.atm

T = temperature = $30.0^oC=273+30.0=303K$

$K$ = equilibrium constant = ?

Now put all the given values in this expression, we get:

$-89400J/mol=-(8.314J/L.atm)\times (303K)\times \ln K$

$K=2.6\times 10^{15}$

Thus, the value of $K$ for this reaction is, $2.6\times 10^{15}$

4 0

3 years ago

Quincy wants to see a real example of rock weathering. Where would be the best place for him to go? A. up on the roof of his hou

zhannawk [14.2K]

Answer:

Option (D)

Explanation:

Weathering is usually defined as the disintegration of rocks at the surface of the earth. This break down of rocks is mainly caused by the geological processes that occur on the earth's surface. This process results in the formation of sediments that are transported and deposited in a new environment.

This weathering process primarily takes place in three different ways such as-

Physical weathering- Here, the rocks are broken down by the physical agents such as wind, water, ice.

Chemical weathering- Here the rocks are broken down when interacts with the chemical containing water.

Biological weathering- here, the rocks are broken down due to the activities done by organisms such as plants and animals.

In the given condition, Quincy can see a real example of rock weathering in the high mountainous region, as in the mountainous region the rocks are frequently weathered and eroded by the agents such as wind, water, and ice.

Thus, the correct answer is option (D).

4 0

3 years ago

How many liters of water vapor are in 36.21 g?

Elden [556K]

Answer:

45.02 L.

Explanation:

Firstly, we need to calculate the no. of moles of water vapor.

n = mass / molar mass = (36.21 g) / (18.0 g/mol) = 2.01 mol.

We can calculate the volume of knowing that 1.0 mole of a gas at STP occupies 22.4 L.

<em><u>Using cross multiplication:</u></em>

1.0 mole of CO occupies → 22.4 L.

2.01 mole of CO occupies → ??? L.

∴ The volume of water vapor in 36.21 g = (22.4 L)(2.01 mole) / (1.0 mole) = 45.02 L.

4 0

2 years ago