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vovikov84 [41]
3 years ago
14

Yes ples omggggggggg

Physics
2 answers:
rjkz [21]3 years ago
4 0
The answer would be A, because blood carries nutrients to all of our body cells.
Alexxx [7]3 years ago
3 0

Answer:

The answer is A.

Explanation:

They both work together to circulate oxygen and blood throughout the body.

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How did science of cartography came in India​
Kobotan [32]

Cartography (the making of maps and charts) is a science because it is a body of knowledge which can be used, built on, and can produce testable hypotheses.

The cartography of India begins with early charts for navigation and constructional plans for buildings. Indian traditions influenced Tibetan and Islamic traditions, and in turn, were influenced by the British cartographers who solidified modern concepts into India's map making

8 0
3 years ago
The speed of sound through oxygen at 0°C is 316 meters per second. The speed of sound through solid copper is 5,010 meters per s
vivado [14]

Answer:

1,450 meters per second

Explanation:

5 0
4 years ago
Read 2 more answers
A correlation coefficient represents what two things
kenny6666 [7]

Answer:

A correlation coefficient represents the following:

1- The direction of the relationship

2- The strength of the relationship

3 0
3 years ago
Consider the following distribution of objects: a 2.00-kg object with its center of gravity at (0, 0) m, a 2.20-kg object at (0,
adelina 88 [10]

Answer:

body position 4 is (-1,133, -1.83)

Explanation:

The concept of center of gravity is of great importance since in this all external forces are considered applied, it is defined by

               x_cm = 1 /M   ∑ x_{i} m_{i}

               y_cm = 1 /M   ∑ y_{i} mi

Where M is the total mass of the body, mi is the mass of each element

give us the mass and position of this masses

body 1

m1 = 2.00 ka

x1 = 0 me

y1 = 0 me

body 2

m2 = 2.20 kg

x2 = 0m

y2 = 5 m

body 3

m3 = 3.4 kg

x3 = 2.00 m

y3 = 0

body 4

m4 = 6 kg

    x4=?

   y4=?

mass center position

x_cm = 0

y_cm = 0

let's apply to the equations of the initial part

X axis

    M = 2.00 + 2.20 + 3.40

    M = 7.6 kg

    0 = 1 / 7.6 (2 0 + 2.2 0 + 3.4 2 + 6 x4)

     x4 = -6.8 / 6

     x4 = -1,133 m

Axis y

    0 = 1 / 7.6 (2 0 + 2.20 5 +3.4 0 + 6 y4)

    y4 = -11/6

    y4 = -1.83 m

body position 4 is (-1,133, -1.83)

7 0
3 years ago
The electric field everywhere on the surface of a thin, spherical shell of radius 0.725 m is of magnitude 899 N/C and points rad
Igoryamba

Answer:

Q = -52.56 nC

Explanation:

The electric field outside a spherical shell is given by

E = \frac{k*Q}{r^{2} }

where:

Q is the net  charge

r is the radius of the spherical shell and E is the electric field magnitude.

Given:

r = 0.725 m

since the field points radially toward the center of the sphere, E = -899 N/C.

k is a constant with a value = 8.99 x 109 Nm²/C².

∴-899  = \frac{8.99*10^{9} *Q}{0.725^{2}  }

Q  = \frac{-899*0.725^{2}  }{8.99*10^{9} }=-5.256*10^{-8}

Q = -52.56 nC

8 0
3 years ago
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