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3 years ago

Everyone experiences a wide range of emotions, but when could they indicate a mental disorder?

Physics

1 answer:

Vikentia [17]3 years ago

7 0

Answer:

Excessive paranoia, worry, or anxiety.

Long-lasting sadness or irritability.

Extreme changes in moods.

Social withdrawal.

Dramatic changes in eating or sleeping patter

Explanation:

hope it helps brainliest if right thx :)

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Please I need help with this :(

Ann [662]

three charged particals are located at the corners of an equil triangle shown in the figure showing let (q 2.20 Uc) and L 0.650

3 0

2 years ago

On the surface of the earth the weight of an object is 200 lb. Determine the height of the

siniylev [52]

Answer:

The height of the object is 5007.4 miles.

Explanation:

Given that,

Weight of object = 200 lb

We need to calculate the value of $Gmm_{e}$

Using formula of gravitational force

$F=\dfrac{Gmm_{e}}{r^2}$

Put the value into the formula

$200=\dfrac{Gmm_{e}}{(3958.756)^2}$

$200\times(3958.756)^2=Gmm_{e}$

$Gmm_{e}=3.134\times10^{9}$

We need to calculate the height of the object

Using formula of gravitational force

$F=\dfrac{Gmm_{e}}{r^2}$

Put the value into the formula

$125=\dfrac{200\times(3958.756)^2}{r^2}$

$r^2=\dfrac{200\times(3958.756)^2}{125}$

$r^2=25074798.5$

$r=\sqrt{25074798.5}$

$r=5007.4\ miles$

Hence. The height of the object is 5007.4 miles.

7 0

3 years ago

Suppose a NASCAR race car rounds one end of the Martinsville Speedway. This end of the track is a turn with a radius of approxim

sergiy2304 [10]

Answer:

10.53m/s²

Explanation:

Centripetal acceleration is the acceleration of an object about a circle. The formula for calculating centripetal acceleration is expressed by:

$a = \frac{v^2}{r}$

v is the velocity of the car = 24.5m/s

r is the radius of the track = 57.0m

Substitute the given values into the formula:

$a = \frac{24.5^2}{57} \\\\a = \frac{600.25}{57}\\ \\a = 10.53m/s^{2}$

Hence the centripetal acceleration of the race car is 10.53m/s²

6 0

3 years ago

IP A spark plug in a car has electrodes separated by a gap of 6.5×10−2 in . To create a spark and ignite the air-fuel mixture in

emmainna [20.7K]

Answer:

a.) $V=5283.2 \ V$

b.) $V=4064\ V$

Explanation:

<u>Electric Field and Potential Difference</u>

There are several conditions that must be met for a spark to be created into an air gap. Once the physical conditions are fixed, a minimum electric field is necessary for the spark to be initiated. Let s be the separation between the electrodes and V their potential difference. The electric field is

a.)

$\displaystyle E=\frac{V}{s}$

Solving for V

$V=E.s$

The separation is

$s= 5.5\cdot 10^{-2}\ in=0.001651 \ m$

Thus the potential difference is

$V=3.2\cdot 10^{6}\ V/m\times 0.001651 \ m$

$V=5283.2 \ V$

b.) If the separation was greater, the applied voltage needs to be greater if the electric field has to be constant. One possible measure to keep electrodes as close as possible is to build them as sharp edges. It gives the spark an easier path to travel to.

If the separation is 0.05 inches =0.00127 m

$V=3.2\cdot 10^{6}\ V/m\times 0.00127 \ m$

$V=4064\ V$

7 0

3 years ago

How would a large bar magnet on earths surface be aligned

Amiraneli [1.4K]

D; it’s north magnetic pole would be pointing toward the geographic south pole

3 0

3 years ago

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