We have the following equation:
y = (5-x) / x ^ 2-6x + 5
Rewriting we have:
y = (5-x) / (x-5) * (x-1)
The discontinuity points are:
x = 5
x = 1
x = 5 is removable. For this, we rewrite the function again:
y = (-1 * (5-x)) / (- 1 * (x-5) * (x-1))
y = ((x-5)) / ((x-5) * (1-x))
We cancel similar terms:
y = 1 / (1-x)
Answer:
the points of discontinuity are:
x = 5
x = 1
x = 5 is removable
through venmo or what?
Step-by-step explanation:
Answer:
B. 9k^2 + 5k - 1
Step-by-step explanation:
4k^2 + 5k - 3 + 5k^2 + 2
= 4k^2 + 5k^2 + 5k - 3 + 2
= 9k^2 + 5k - 1
Answer:


Step-by-step explanation:
We have the following equation:

We can use the quadratic formula given by:

Where:

And replacing we got:


503
x 9
———
4,527
This works good with the factors because you work step by step, making an equation like this one