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3 years ago

What is the price of 0.75 m of fabric if the meter costs 31,500

Mathematics

1 answer:

skad [1K]3 years ago

8 0

Look up what is 75% of 31,500

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There are nine tennis balls and three cans

tester [92]

Answer: 0.33 repeating

Step-by-step explanation: 3 divided by 9

6 0

3 years ago

Help please! I need to write 4y =-3x + 12 in standard form, find the y-intercept of the previous equation, as an ordered pair, a

damaskus [11]

Answer:

$-3x+4y=12\\y-intercept: (0,3)\\x-intercept: (-4,0)$

Step-by-step explanation:

The standard form of a linear equation is $ax+by=c$ , where $a$ , $b$ , and $c$ are constants in the equation.

Based on the equation you have provided, the standard form would be $-3x+4y=12$ , where $a=-3, b=4, c=12$ .

To find the y-intercept, set $x=0$ .

$-3(0)+4y=12\\0+4y=12\\4y=12\\y=\frac{12}{4} =3$

Therefore, the y-intercept is $(0,3)$ .

Do the same thing for the x-intercept, but this time with $y=0$ .

$-3x+4(0)=12\\-3x+0=12\\-3x=12\\x=\frac{12}{-3} =-4$

Therefore, the x-intercept is $(-4,0)$ .

5 0

3 years ago

Psychologist Michael Cunningham conducted a survey of university women to see whether, upon graduation, they would prefer to mar

bagirrra123 [75]

Answer:

A.The probability that exactly six of Nate's dates are women who prefer surgeons is 0.183.

B. The probability that at least 10 of Nate's dates are women who prefer surgeons is 0.0713.

C. The expected value of X is 6.75, and the standard deviation of X is 2.17.

Step-by-step explanation:

The appropiate distribution to us in this model is the binomial distribution, as there is a sample size of n=25 "trials" with probability p=0.25 of success.

With these parameters, the probability that exactly k dates are women who prefer surgeons can be calculated as:

$P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}\\\\\\P(x=k) = \dbinom{25}{k} 0.25^{k} 0.75^{25-k}\\\\\\$

A. P(x=6)

$P(x=6) = \dbinom{25}{6} p^{6}(1-p)^{19}=177100*0.00024*0.00423=0.183\\\\\\$

B. P(x≥10)

$P(x\geq10)=1-P(x$

$P(x=0) = \dbinom{25}{0} p^{0}(1-p)^{25}=1*1*0.0008=0.0008\\\\\\P(x=1) = \dbinom{25}{1} p^{1}(1-p)^{24}=25*0.25*0.001=0.0063\\\\\\P(x=2) = \dbinom{25}{2} p^{2}(1-p)^{23}=300*0.0625*0.0013=0.0251\\\\\\P(x=3) = \dbinom{25}{3} p^{3}(1-p)^{22}=2300*0.0156*0.0018=0.0641\\\\\\P(x=4) = \dbinom{25}{4} p^{4}(1-p)^{21}=12650*0.0039*0.0024=0.1175\\\\\\P(x=5) = \dbinom{25}{5} p^{5}(1-p)^{20}=53130*0.001*0.0032=0.1645\\\\\\P(x=6) = \dbinom{25}{6} p^{6}(1-p)^{19}=177100*0.0002*0.0042=0.1828\\\\\\$

$P(x=7) = \dbinom{25}{7} p^{7}(1-p)^{18}=480700*0.000061*0.005638=0.1654\\\\\\P(x=8) = \dbinom{25}{8} p^{8}(1-p)^{17}=1081575*0.000015*0.007517=0.1241\\\\\\P(x=9) = \dbinom{25}{9} p^{9}(1-p)^{16}=2042975*0.000004*0.010023=0.0781\\\\\\$