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Olenka [21]
2 years ago
6

SECTIONA ANSWERALL QUESTIONS (5 MARKS PER QUESTION) 1:03 mixing a solution of silver nitrate and dilute hydrochloric acid a whit

e precipitate is :o:med inrmediately. 1) Write an equation for the reaction (ii) The precipitate darkens rapidly upon standing. Why? :12 Explain why conductivity measurements of M* in aqueous solutions is in the order: Cs' > Rb'>K" > Na* > Li' A3 Why is it that lithium salts are often hydrated whereas those of the other alkali metals are ofien anhydrous? 44 Explain with the help of chemical equations why BeCl2 is acidic .45(a) State the main types of bonds formed by hydrogen Star lo list three ways of preparing hydrogen 16 Write an equation and identify the element formed when: (a) Polonium 210 undergoes a- decay (b) Actrium 277 undergoes ß- decay (0) Iridium 186 undergoes electron capture d) Bismuth 192 undergoes positron emission (C) Iodine 133 undergoes B- emission 47 The Uranium decay series starts with 238,2Uand ends with 206,2Pb. Each step involves the Luistentie​
Chemistry
1 answer:
kenny6666 [7]2 years ago
8 0

Answer:..,.,

Explanation:88.,,'

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Where is carbon dioxide found in nature​
deff fn [24]

Explanation:

the air you breathe is called carobon dioxide = co

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3 years ago
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Calculemos la formula empirica y molecular de carbonato de hierro Fe2(co3)3.Fe.38.3%C.12.3%.0.4 92% masa 292g
DENIUS [597]

Respuesta:

292 g / mol;

Por favor, consulte la explicación.

Explicación:

El número de átomos de cada elemento en el compuesto: Fe2 (co3) 3.

Fe = 2; C = 3; 0 = 3 * 3 = 9

Fe2 = 112 g / mol

C = 12 g / mol

O = 16 g /

Masa molecular = ((112 + (12 * 3) + (16 * 9)

= (112 + 36 + 144)

= 292 g / mol.

Total = 2 + 3 + 9 = 14

Fe2 = 112/292 * 100% = 38,356%

C = 36/292 * 100% = 12,328 * '

O = (16 * 9) / 292 * 100% = 49,32%

7 0
3 years ago
A student constructs a coffee cup calorimeter and places 50.0 mL of water into it. After a brief period of stabilization, the te
Grace [21]

Answer:

The calorimeter constant is  = 447 J/°C

Explanation:

The heat absorbed or released (Q) by water can be calculated with the following expression:

Q = c × m × ΔT

where,

c is the specific heat

m is the mass

ΔT is the change in temperature

The water that is initially in the calorimeter (w₁) absorbs heat while the water that is added (w₂) later releases heat. The calorimeter also absorbs heat.

The heat absorbed by the calorimeter (Q) can be calculated with the following expression:

Q = C × ΔT

where,

C is the calorimeter constant

The density of water is 1.00 g/mL so 50.0 mL = 50.0 g. The sum of the heat absorbed and the heat released is equal to zero (conservation of energy).

Qabs + Qrel = 0

Qabs = - Qrel

Qcal + Qw₁ = - Qw₂

Qcal = - (Qw₂ + Qw₁)

Ccal . ΔTcal = - (cw . mw₁ . ΔTw₁ + cw . mw₂ . ΔTw₂)

Ccal . (30.31°C - 22.6°C) = - [(4.184 J/g.°C) × 50.0 g × (30.31°C - 22.6°C) +  (4.184 J/g.°C) × 50.0 g × (30.31°C - 54.5°C)]

Ccal  = 447 J/°C

5 0
3 years ago
What is the density (g/mL) of an object that has a mass of 0.03 kg and occupies a volume of 25 mL?
tatyana61 [14]
First convert the kg to g ----- 0.03kg = 30g
Then divide the mass by the volume ----- 30g ÷ 25mL = 1.2
The density is 1.2g/mL<span />
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3 years ago
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6. The modern view of the atom has come a long way from that of a solid, indestructible sphere
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It is a true statement
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