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3 years ago

What would be the formula for diphosphorus pentoxide? A. PO5 B. P2O5 C. P5O D. P5O2

Chemistry

2 answers:

Dovator [93]3 years ago

6 0

I am sure, the answer is variant B.

Nookie1986 [14]3 years ago

4 0

heeeeeeyyyyyy yalllllll the answer is B!!!!!!!!!!!

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Phuong trinh phan ung ohc cho +02

scZoUnD [109]

Answer:

yes

hope this helps!!!!

5 0

2 years ago

An atom has a mass number of 24 and 13 neutrons. What is the atomic number of this atom? Express

Temka [501]

A=mass number (protons + neutrons)
Z=atomic number (protons)
N=number of neutrons.

A=Z+N

Data:
A=24
N=13

Therefore:
24=Z+13
Z=24-13=11

Answer: The atomic number of this atom is 11. (The element is sodium)

8 0

3 years ago

ou will prepare 250-mL of this solution using a 30% (m/v) NaOH stock solution. How many mL of the NaOH stock solution will you n

ArbitrLikvidat [17]

Answer:

$\boxed{\text{3.3 mL}}$

Explanation:

You must convert 30 % (m/v) to a molar concentration.

Assume 1 L of solution.

1. Mass of NaOH

$\text{Mass of NaOH} = \text{1000 mL solution } \times \dfrac{\text{30 g NaOH}}{\text{100 mL solution}} = \text{300 g NaOH}$

2. Moles of NaOH

$\text{Moles of NaOH} = \text{300 g NaOH} \times \dfrac{\text{1 mol NaOH}}{\text{40.00 g NaOH}} = \text{7.50 mol NaOH}$

3. Molar concentration of NaOH

$c= \dfrac{\text{moles}}{\text{litres}} = \dfrac{\text{7.50 mol}}{\text{1 L}} = \text{7.50 mol/L}$

4. Volume of NaOH

Now that you know the concentration, you can use the dilution formula .

$c_{1}V_{1} = c_{2}V_{2}$

to calculate the volume of stock solution.

Data:

c₁ = 7.50 mol·L⁻¹; V₁ = ?

c₂ = 0.1 mol·L⁻¹; V₂ = 250 mL

Calculations:

(a) Convert millilitres to litres

$V = \text{250 mL} \times \dfrac{ \text{1 L}}{\text{1000 mL}} = \text{0.250 L}$

(b) Calculate the volume of dilute solution

$\begin{array}{rcl}7.50V_{1} & = & 0.1 \times 0.250\\7.50V_{1} &= & 0.0250\\V_{1} & = & \text{0.0033 L}\\& = & \textbf{3.3 mL}\\\end{array}$

$\text{You will need $\boxed{\textbf{3.3 mL}}$ of the stock solution.}$

4 0

3 years ago

Q1.

valentinak56 [21]

Answer:

4.49dm3

Explanation:

2NH4Cl + Ca(OH)2 —> CaCl2 + 2NH3 + 2H2O

First, we need to convert 10g of ammonium chloride to mole. This is illustrated below:

Molar Mass of NH4Cl = 14 + (4x1) + 35.5 = 53.5g/mol

Mass of NH4Cl = 10g

Number of mole = Mass /Molar Mass

Number of mole of NH4Cl = 10/53.5 = 0.187mol

From the equation,

2moles of NH4Cl produced 2 moles of NH3.

Therefore, 0.187mol of NH4Cl will also produce 0.187mol of NH3

Now we can obtain the volume of NH3 produced by doing the following:

1mole of any gas occupy 24dm3

Therefore, 0.187mol of NH3 will occupy = 0.187 x 24 = 4.49dm3

4 0

3 years ago

predict whether a gold ring would be a good conductor of electricity. What kind of bonds does gold have. How do these bonds expl

ANTONII [103]

Gold is a chemical element with the place on the periodic table of AU (from Latin aurum.) It is a pure form of metal, making it a conductor. As you know, metal is a conductor. It does retain its conductivity due to the lack of tarnishing. Though silver and copper are better with conducting, gold would make a decent conductor.

4 0

3 years ago