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3 years ago

If 4500 g of Zr metal is reacted with 1.5 x 104 g of water what is the limiting reactant?

Chemistry

1 answer:

PIT_PIT [208]3 years ago

6 0

Answer:

Explanation:

The balance equation of the reaction is:

Zr + 2 H₂O ⇒ ZrO₂ + 2 H₂

Being:

Zr: 91 g/mole
H: 1 g/mole
O: 16 g/mole

the molar mass of the reactants participating in the reaction are:

Zr: 91 g/mole
H₂O: 2*1 g/mole + 16 g/mole= 18 g/mole

If by stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction) they react in moles:

Zr: 1 mole
H₂O: 2 moles

then by stoichiometry the following quantity of mass react:

Zr: 1 mole*91 g/mole= 91 g
H₂O: 2 moles*18 g/mole= 36 g

Now the following rule of three applies: if 91 g of Zr react with 36 g of H₂O, 4500 g of Zr with how much mass of H₂O would it react?

$mass of H_{2} O=\frac{4500 grams of Zr*36 grams of H_{2}O }{91 grams of Zr}$

mass of H₂O= 1,780 grams

But 1780 grams of H₂0 are not available, 1.5 * 10⁴(15,000) grams are available. Since it has more mass than it needs to react with 4500 grams of Zr, Zr zirconia will be the limiting reagent.

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A lab scientist cools a liquid sample of water (2.6 kg) at 0.00°C to -192°C. The water turns to ice as this temperature change o

soldier1979 [14.2K]

Answer: The heat released for the given process is -1892 kJ

Explanation:

The processes involved in the given problem are:

$1.)H_2O(l)(0^oC,273K)\rightarrow H_2O(s)(0^oC,273K)\\2.)H_2O(s)(0^oC,273K)\rightarrow H_2O(s)(-192^oC,81K)$

Pressure is taken as constant.

To calculate the amount of heat released at same temperature, we use the equation:

$q=m\times L_{f,v}$ ......(1)

where,

q = amount of heat released = ?

m = mass of water/ice

$L_{f,v}$ = latent heat of fusion or vaporization

To calculate the amount of heat released at different temperature, we use the equation:

$q=m\times C_{p,m}\times (T_{2}-T_{1})$ .......(1)

where,

q = amount of heat released = ?

$C_{p,m}$ = specific heat capacity of medium

m = mass of water/ice

$T_2$ = final temperature

$T_1$ = initial temperature

Calculating the heat absorbed for each process:

For process 1:

Converting the latent heat of fusion in J/kg, we use the conversion factor:

1 kJ = 1000 J

So, $(\frac{-334kJ}{1kg})\times (\frac{1000J}{1kJ})=-334\times 10^3J/kg$

We are given:

$m=2.6kg\\L_f=-334\times 10^3J/kg$

Putting values in equation 1, we get:

$q_1=2.6kg\times (-334\times 10^3J/kg)=-868400J$

For process 2:

We are given:

$m=2.6kg\\C_{p,s}=2050J/kg.K\\T_1=273K\T_2=81K$

Putting values in equation 2, we get:

$q_2=2.6kg\times 2050J/kg.K\times (81-(273))^oC\\\\q_2=1023360J$

Total heat absorbed = $q_1+q_2$

Total heat absorbed = $[-868400+(-1023360)]J=-1891760J=-1891.76kJ\approx -1892kJ$

Hence, the heat released for the given process is -1892 kJ

3 0

3 years ago

Which statement correctly compares the sun and planets? A. Planets have an atmosphere; the sun does not. B. Planets gives off en

likoan [24]

Answer:

Explanation:

because the sun is at the center of the universe the planet orbit the sun its basically a simple answer so if you need more help im right here

8 0

3 years ago

In the following reaction, how many grams of nitroglycerin C3H5(NO3)3 will decompose to give 25 grams of CO2?

gogolik [260]

4C₃H₅(NO₃)₃ $_{(l)}$ ------> 12CO₂ $_{(g)}$ + 6N₂ $_{(g)}$ + 10H₂O $_{(g)}$ + O₂ $_{(g)}$

mol of CO₂ = $\frac{mass}{molar mass}$

= $\frac{25g}{44.01 g/mol}$

mol ratio of CO₂ : C₃H₅(NO₃)₃

12 : 4

∴ if mole of CO₂ = 0.568 mol

then " " C₃H₅(NO₃)₃ = $\frac{0.568 mol}{12} * 4$

= 0.189 mol

∴ mass of nitroglycerin = mole * Mr

= 0.189 mol * 227.0995 g / mol

= 43.00 g

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3 years ago

When balance the following chemical equations N2+O2= NO2 the coefficient for O2 is

Papessa [141]

Answer:

Explanation:

N₂ + O₂ ---> NO₂

balance

N₂ + 2O₂ ---> 2NO₂

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3 years ago

According to the National Institute of Health, ventricular tachycardia is a fast, regular beating of the ventricles that may las

jarptica [38.1K]

Answer:

1 makes the most sense

Explanation:

There is no way blood pressure will be decreased especially if your ventricles are erratically contracting for a long period of time. So 3 and 4 are out. And you said number 2 is wrong so my finally answer is 1.

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3 years ago