If 4500 g of Zr metal is reacted with 1.5 x 104 g of water what is the limiting reactant?
1 answer:
Answer:
Zr
Explanation:
The balance equation of the reaction is:
Zr + 2 H₂O ⇒ ZrO₂ + 2 H₂
Being:
- Zr: 91 g/mole
- H: 1 g/mole
- O: 16 g/mole
the molar mass of the reactants participating in the reaction are:
- Zr: 91 g/mole
- H₂O: 2*1 g/mole + 16 g/mole= 18 g/mole
If by stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction) they react in moles:
- Zr: 1 mole
- H₂O: 2 moles
then by stoichiometry the following quantity of mass react:
- Zr: 1 mole*91 g/mole= 91 g
- H₂O: 2 moles*18 g/mole= 36 g
Now the following rule of three applies: if 91 g of Zr react with 36 g of H₂O, 4500 g of Zr with how much mass of H₂O would it react?
mass of H₂O= 1,780 grams
But 1780 grams of H₂0 are not available, 1.5 * 10⁴(15,000) grams are available. Since it has more mass than it needs to react with 4500 grams of Zr, Zr zirconia will be the limiting reagent.
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Answer:
You need 8,324 g of CaCl₂ yo make this solution
Explanation:
Molarity is a way to express concentration in a solution, in units of moles of solute per liter of solution.
To know the grams of CaCl₂ it is necessary to know, first, the moles of this substance with the desired volume and concentration , thus:
0,1500 L × = 0,075 CaCl₂ moles
Now, with the molar mass of CaCl₂ you will obtain the necessary grams, thus:
0,075 CaCl₂ moles × = 8,324 g of CaCl₂
So, you need <em>8,324 g of CaCl₂</em> to make 150,0 mL of a 0,500M solution
I hope it helps!
Answer: Lanthanide and actinide series
Explanation: The elements with partially or fully filled f orbitals belong to f block elements.
f block elements include lanthanides and actinides. They are called so the lanthanides contain the first element named as lanthanum and actinides contain first element named as actinium. They are also called as inner transition elements.
All of them have general electronic configuration:
, where n = 6-7