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Alla [95]
3 years ago
5

PLZ I need help!!!!!

Mathematics
1 answer:
shusha [124]3 years ago
3 0

Answer:

The Answers are

\csc (-45) =-\sqrt{2} \\\\\sec (-45) = \sqrt{2}\\\\\cot (-45) = -1

Step-by-step explanation:

Let we Know some Identities

cosec (-θ) = - cosec (θ)

   sec (-θ) = sec (θ)

    cot (-θ) = - cot (θ)

Also,

\csc (45) =\sqrt{2} \\\\\sec (45) = \sqrt{2}\\\\\cot (45) = 1

Therefore,

\csc (-45) =-\csc (45)=-\sqrt{2} \\\\\sec (-45) =\sec (45) =\sqrt{2}\\\\\cot (-45) =-\cot (45)= -1

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For every function you need evaluate the function for every value in the domain D. And the collection of this values correspond to the range of the function.

1. D = \{0,1,2,3 \}, R = \{f(0), f(1), f(2), f(3) \} = \{-5, -2, 1, 4 \}.

2. D = \{-1,0,1 \}; R= \{f(-1), f(0), f(1)\} = \{0, 1, 0 \} = \{0,1\}

3. D = \{-2,-1,0,1 \}; R = \{f(-2), f(-1), f(0), f(1) \} = \{0, -2, -2, 0 \} = \{-2,0\}

4. D = \{0,1,2,3 \}; R =\{f(0), f(1), f(2), f(3) \} = \{3, 1, -1, -3 \}

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3 years ago
One gallon of paint is equivalent to 3.78 liters.Michael wants to determine how many centiliters this is.Which answer choice is
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Step-by-step explanation

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2 years ago
5 ( x + 3 - 5x)<br> PLZ WHAT IS THIS IN SIMPLEIST FORM WILL GIVE BRAINLIEST
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Step-by-step explanation:

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3 years ago
Read 2 more answers
If m&lt;BEG = (19x + 3)° and m&lt;EGC = (m&lt;GCB + 4x)°, which of the following statements is true about quadrilateral BEGC? Se
viktelen [127]

Answer:

The sum of all exterior angles of BEGC is equal to 360° ⇒ answer F only

Step-by-step explanation:

* Lets revise some facts about the quadrilateral

- Quadrilateral is a polygon of 4 sides

- The sum of measures of the interior angles of any quadrilateral is 360°

- The sum of measures of the exterior angles of any quadrilateral is 360°

* Lets solve the problem

- DEGC is a quadrilateral

∵ m∠BEG = (19x + 3)°

∵ m∠EGC = (m∠GCB + 4x)°

∵ The sum of the measures of its interior angles is 360°

∴ m∠BEG + m∠EGC + m∠GCB + m∠CBE = 360

∴ (19x + 3) + (m∠GCB + 4x) + m∠GCB + m∠CBE = 360 ⇒ add the like terms

∴ (19x + 4x) + (m∠GCB + m∠GCB) + m∠CBE + 3 = 360 ⇒ -3 from both sides

∴ 23x + 2m∠GCB + m∠CBE = 375

∵ The sum of measures of the exterior angles of any quadrilateral is 360°

∴ The statement in answer F is only true

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3 years ago
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