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Alla [95]
3 years ago
5

PLZ I need help!!!!!

Mathematics
1 answer:
shusha [124]3 years ago
3 0

Answer:

The Answers are

\csc (-45) =-\sqrt{2} \\\\\sec (-45) = \sqrt{2}\\\\\cot (-45) = -1

Step-by-step explanation:

Let we Know some Identities

cosec (-θ) = - cosec (θ)

   sec (-θ) = sec (θ)

    cot (-θ) = - cot (θ)

Also,

\csc (45) =\sqrt{2} \\\\\sec (45) = \sqrt{2}\\\\\cot (45) = 1

Therefore,

\csc (-45) =-\csc (45)=-\sqrt{2} \\\\\sec (-45) =\sec (45) =\sqrt{2}\\\\\cot (-45) =-\cot (45)= -1

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Answer:

not statistically significant at ∝ = 0.05

Step-by-step explanation:

Sample size( n )  = 61

Average for student leader graduates to finish degree ( x') = 4.97 years

std = 1.23

Average for student body = 4.56 years

<u>Determine if the difference between the student leaders and the entire student population is statistically significant at alpha</u>

H0( null hypothesis ) : u = 4.56

Ha : u ≠ 4.56

using test statistic

test statistic ; t = ( x' - u ) / std√ n

                        = ( 4.97 - 4.56 ) / 1.23 √ 61

                        = 2.60

let ∝ = 0.05 , critical value = -2.60 + 2.60

Hence we wont fail to accept  H0

This shows that the difference between the student leaders and the entire student population is not statistically significant at ∝ = 0.05

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3 years ago
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Then
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