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frez [133]
3 years ago
7

PLEASE HELP MAX POINTS AND BRAINLIEST!!!Find the length of the longest nail that could fit entirely within a cylindrical can of

radius 2 inches and height of 6 inches.​
Mathematics
2 answers:
Kamila [148]3 years ago
7 0

Answer:

The length is 7.21 inches

Step-by-step explanation:

Cylinder:

r = 2

h = 6

To get diameter we do d = 2r

d = 4

Nail = triangle shape so:

Triangle ABC

AC² = AB² + BC²

AC² = 6² + 4²

AC² = 36 + 16

AC² = 52

\sqrt{AC^2} =\sqrt{52}

AC = 7.21

The length is 7.21 inches

GalinKa [24]3 years ago
6 0

Answer:

a 7.2 inch nail

Step-by-step explanation:

using the Pythagorean theorem:

the diagonal distance of a 6" height and a 2" radius (4" diameter) would be:

D² = 6² + 4² = 36 + 16 = 52

D = √52 = 7.21 inches

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Step-by-step explanation:

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We have to find the solution of given inequality.

Adding -6 to both sides of above inequality, we have

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