Answer: B. There are more boys at Mark's school than at Leslie's school because the ratio 41 to 48 is greater than the ratio 11 to 12.
Step-by-step explanation:
Here are the options:
A There are more boys at Mark's school than at Leslie's school because the ratio 11 to 12 is greater than the ratio 41 to 48.
B. There are more boys at Mark's school than at Leslie's school because the ratio 41 to 48 is greater than the ratio 11 to 12.
C. There are more boys at Leslie's school than at Mark's school because the ratio 41 to 48 is greater than the ratio 11 to 12.
At leslie's school the ratio of boys and girls is 11 to 12. This implies that the fraction of boys in the school to total students will be:
= 11/(11 + 12) = 11/23 = 0.4783
At Marks school the ratio of boys to girls is 41 to 48. Thus implies that the fraction of boys in the school to total students will be:
= 41 / (41 + 48) = 41/85= 0.4824
Based on the calculation, we can deduce that there are more boys at Mark's school than at Leslie's school because the ratio 41 to 48 is greater than the ratio 11 to 12.
Answer:
yes it is right
Step-by-step explanation:
Answer:
The proof is below
Step-by-step explanation:
Given a parallelogram ABCD. Diagonals AC and BD intersect at E. We have to prove that AE is congruent to CE and BE is congruent to DE i.e diagonals of a parallelogram bisect each other.
In ΔACD and ΔBEC
AD=BC (∵Opposite sides of a parallelogram are equal)
∠DAC=∠BCE (∵Alternate angles)
∠ADC=∠CBE (∵Alternate angles)
By ASA rule, ΔACD≅ΔBEC
By CPCT(Corresponding Parts of Congruent triangles)
AE=EC and DE=EB
Hence, AE is conruent to CE and BE is congruent to DE
Given parameters:
Net worth of Cesar = 8250.63
Liabilities = 3222.35
Unknown:
Cesar's asset = ?
Solution:
A person's net worth is their Assets minus liability;
Net worth = Assets - Liabilities
Assets = Net worth + Liabilities
For Cesar;
Assets = 8250.63 + 3222.35 = 11472.98
Cesar's assets is 11472.98
Answer:
the -3.2+8.1 is 4.9 I can't see the rest
