Question

A rectangular bathroom floor is covered with square tiles that are 1 LaTeX: \frac{1}{2}1 2 feet by 1 LaTeX: \frac{1}{2}1 2 feet. The length of the bathroom floor is 10 LaTeX: \frac{1}{2}1 2 feet and the width is 6 LaTeX: \frac{1}{2}1 2 feet. a) How many tiles does it take to cover the length of the floor?

Answer 1

Answer:

273 tiles

Step-by-step explanation:

Given

Square tile

$Side=\frac{1}{2} ft$

Bathroom floor

$Length = 10\frac{1}{2}ft$

$Width = 6\frac{1}{2}ft$

Required

Determine the number of tiles to cover the floor

First, we calculate the area of the floor:

$A_{floor} = Length * Width$

$A_{floor} = 10\frac{1}{2} * 6\frac{1}{2}$

Convert to decimals

$A_{floor} = 10.5 * 6.5$

$A_{floor} = 68.25ft^2$

Next, we calculate the area of the square tile:

$A_{tile} = Side * Side$

$A_{tile} = \frac{1}{2} * \frac{1}{2}$

Convert to decimal

$A_{tile} = 0.5 * 0.5$

$A_{tile} = 0.25ft^2$

The number of tiles is then calculated as:

$Tiles = \frac{A_{floor}}{A_{tile}}$

$Tiles = \frac{68.25ft^2}{0.25ft^2}$

$Tiles = \frac{68.25}{0.25}$

$Tiles = 273$