Potassium Iodide have a lot of strong bonds which requires a very high temperature (high energy) to break them and change into a different state of matter.
The reaction yields the product compound 2,4,5-tribromophenol.
<h3>Bromination of monohydroxy benzene</h3>
Bromination is an organic reaction in which aqueous bromine is made to react with another compound so as to introduce bromine into the molecule.
When we carry out the bromination of monohydroxy benzene, we obtain the compound 2,4,5-tribromophenol.
Learn more about benzene: brainly.com/question/14525517
the answer is 0.000097 KM
Answer:
a) Ka= 7.1 × 10⁻⁴; This is a weak acid because the acid is not completely dissociated in solution.
Explanation:
Step 1: Write the dissociation reaction for nitrous acid
HNO₂(aq) ⇄ H⁺(aq) and NO₂⁻(aq)
Step 2: Calculate the acid dissociation constant
Ka = [H⁺] × [NO₂⁻] / [HNO₂]
Ka = 0.022 × 0.022 / 0.68
Ka = 7.1 × 10⁻⁴
Step 3: Determine the strength of the acid
Since Ka is very small, nitrous acid is a weak acid, not completely dissociated in solution.
