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omeli [17]
2 years ago
11

What is the atomic mass of Sulfur?

Chemistry
2 answers:
VikaD [51]2 years ago
3 0

Answer:

32.065 u

Explanation:

tekilochka [14]2 years ago
3 0

Answer:

The correct answer is 32.065

Explanation:

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34 atoms of carbon (C) react with 22 molecules of hydrogen gas (H2). How many molecules of methane (CH4) will be formed, and wha
kolbaska11 [484]

Answer:

11 molecules of CH4.

23 atoms of C is the leftover.

Explanation:

Hello!

In this case, for the formation of methane:

C+2H_2\rightarrow CH_4

We can see there is an excess of carbon based on their stoichiometry, because the needed amount of hydrogen gas molecules would be:

molecules _{H_2}=34atomC*\frac{2molec\ H_2}{1atomC} =68molec\ H_2

Thus, the formed molecules of methane are computed below:

molec\ CH_4=22molec\ H_2 *\frac{1molec\ CH_4}{2molmolec\ H_2} \\\\molec\ CH_4=11molec\ CH_4

In such a way, the leftover of carbon atoms are:

atoms \ C^{left over}=34-22molec\ H_2*\frac{1atoms C}{2molec\ H_2} \\\\atoms \ C^{left over}=23 atoms C

Best regards!

4 0
3 years ago
A chemistry student needs 50.0 g of methyl acetate for an experiment. By consulting the CRC Handbook of Chemistry and Physics, t
slamgirl [31]

Explanation:

As density is defined as the mass of a substance divided by its volume.

Mathematically,         Density = \frac{mass}{volume}

It is given that mass is 50 g and density is 0.934 g/cm^{3}.

Hence, calculate the volume of methyl acetate as follows.

                     Density = \frac{mass}{volume}

             0.934 g/cm^{3} = \frac{50 g}{volume}

                       Volume = 53.53 cm^{3}

or,                                  = 53.53 ml                (as 1 cm^{3} = 1 mL)

Thus, we can conclude that the volume of methyl acetate the student should pour out is 53.53 ml.

3 0
3 years ago
A formula unit made with Na and unknown nonmetal "Z" has the formula, NaZ. Which element does "Z" represent?
vovangra [49]
The answer is chloride ig ‍♀️
6 0
3 years ago
A Helium Balloon contains 24.3 moles of Helium Gas. How many grams of Helium is this?
Gnesinka [82]
Mass= number of moles multiply Mass of one mole
= 24.3 multiplied by 4
= 96.2
4 0
3 years ago
Read 2 more answers
The density of potassium, which has the BCC structure, is 0.855 g/cm3. The atomic weight of potassium is 39.09 g/mol. Calculate
Delicious77 [7]

<u>Answer:</u>

<u>For a:</u> The edge length of the crystal is 533.5 pm

<u>For b:</u> The atomic radius of potassium is 231.01 pm

<u>Explanation:</u>

  • <u>For a:</u>

To calculate the lattice parameter or edge length of the crystal, we use the equation:

\rho=\frac{Z\times M}{N_{A}\times a^{3}}

where,

\rho = density = 0.855g/cm^3

Z = number of atom in unit cell = 2  (BCC)

M = atomic mass of metal = 39.09 g/mol

N_{A} = Avogadro's number = 6.022\times 10^{23}

a = edge length of unit cell = ?

Putting values in above equation, we get:

0.855=\frac{2\times 39.09}{6.022\times 10^{23}\times (a)^3}\\\\\a=5.335\times 10^{-8}cm=533.5pm

<u>Conversion factor:</u>  1cm=10^{10}pm

Hence, the edge length of the crystal is 533.5 pm

  • <u>For b:</u>

To calculate the edge length, we use the relation between the radius and edge length for BCC lattice:

R=\frac{\sqrt{3}a}{4}

where,

R = radius of the lattice = ?

a = edge length = 533.5 pm

Putting values in above equation, we get:

R=\frac{\sqrt{3}\times 533.5}{4}=231.01pm

Hence, the atomic radius of potassium is 231.01 pm

4 0
3 years ago
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